The probability that I will end up with one card from each suit is 3/32 when I choose four cards from a standard-card deck, with replacement. This can be obtained by finding probability of each draw.
<h3>What is the required probability?</h3>
- The probability of drawing first card is one, that is the card can be of any suite.
- The probability of drawing second card is,
⇒ 52 cards - 13 cards (1 suite) = 39 cards (remaining 3 suites)
On the second draw, we have a (39/52) = (3/4) probability of drawing a different suite from the first draw
- The probability of drawing third card is,
⇒ 52 cards - 26 cards (2 suite) = 26 cards (remaining 2 suites)
On the third draw we have a (26/52) = (1/2) probability of drawing a suite different from the first two draws
- The probability of drawing fourth card is,
⇒ 52 cards - 39 cards (3 suite) = 13 cards (remaining 1 suites)
On the last draw we have a (13/52) = (1/4) probability of drawing a different suite from the ones we drew on the first three draws
So the probability = (1) (3/4) (1/2) (1/4) = 3/32
Hence the probability that I will end up with one card from each suit is 3/32 when I choose four cards from a standard-card deck, with replacement.
Learn more about probability here:
brainly.com/question/17058636
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