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pav-90 [236]
1 year ago
13

A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45

kmph in the same direction. In how much time will the train pass the jogger?.
Mathematics
1 answer:
Lapatulllka [165]1 year ago
5 0

The train will pass the jogger in 36 seconds.

Length of train = 120m

Speed of train = 45kmph

Distance by which the jogger is ahead of the engine of the train = 240 m

Speed of jogger = 9 kmph

To pass the jogger, the train will have to cover the length of the train and the distance by which the jogger is ahead of the engine of train.

Hence,

Distance = 120 + 240 = 360m

As,

Time = Distance/Speed

Relative speed of train w.r.t jogger = 45 - 9 = 36 kmph = 10 m/s

Hence,

Time = 360/10 = 36 seconds.

To learn more about train, here:-

brainly.com/question/21218609

#SPJ4

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Answer:

The correct answer is no.

Step-by-step explanation:

If a number is a factor of another number, that means that it can be equally divided into it <em>evenly</em>.

I know that 3 x 20 = 60, and 73 - 60 = 13.

Since 3 is <em>not</em> a factor of 13, it is also <em>not</em> a factor of 73.

Hope this helps! :D

6 0
2 years ago
Overview
Alisiya [41]

Answer:

125.4

Step-by-step explanation:

Given

Number = 125.3546

Required

Round to 1 decimal place

Up till the first decimal place, the number is:

Number = 125.3

The digit after .3 is 5

The conditions for approximation are:

  • If n > 4, approximate to 1
  • Else: approximate to 0

In this case: 5 > 4, so we approximate to 1

Add this "1" to the last digit of 125.3. This becomes 125.4

<em>Hence: when the number is approximated to 1 decimal place, the digit is 125.4</em>

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2 years ago
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Which of the following is a conditional statement?
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What is the result when 4x3 + 19x2 + 29x + 14 is divided by 4x + 7?
Sergio039 [100]

Step-by-step explanation:

4x³ + 19x² + 29x + 14

= (4x³ + 7x²) + (12x² + 21x) + (8x + 14)

= x²(4x + 7) + 3x(4x + 7) + 2(4x + 7).

= (x² + 3x + 2)(4x + 7).

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3 0
2 years ago
Read 2 more answers
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