Answer:
Every ordered pair within this region will satisfy the inequality y ≥ x. Incorrect. The boundary line here is y = x, and the correct region is shaded, but remember that a dotted line is used for < and >. The inequality you are graphing is y ≥ x, so the boundary line should be solid.
The rate that is equivalent to the rate Paula walked is 1/20 mile/minute OR 0.05 mile/minute
<h3>Calculating Rate </h3>
From the question, we are to determine the rate which is equivalent to the rate Paula walked
Using the formula,

From the given information,
Distance = 1/12 mile
Time = 5/3 minutes
Putting the parameters into the formula, we get




mile/minute
Hence, the rate that is equivalent to the rate Paula walked is 1/20 mile/minute OR 0.05 mile/minute
Learn more on Calculating Rate here: brainly.com/question/21208007
#SPJ 1
Lets review the options one by one:
X A.) The question says the y must be <u>less than</u> 100, not less than or equal to.
X B.) The y becomes 0, but 0 is neutral, not a positive number.
X C.) The height must be positive at all times, according to the range given.
√ D.) The given graph contains a max with a positive number under 100.
Therefore, the correct answer choice would be Option D (4).
<em>Hope this helps! :)</em>
Answer:
SOLVE FOR X, Y
x=12
y=−6
Step-by-step explanation:
~To explore/find new lands
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