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NeTakaya
3 years ago
5

Rachel, Mario and Sanjit share some money in the ratios 4 : 3 : 9 Mario receives £96. Work out the difference between the amount

received by Rachel and the amount received by Sanjit.
Mathematics
1 answer:
joja [24]3 years ago
4 0

Answer:

Step-by-step explanation:

If Marios share is 3 parts and is £96, then

Find one part = 96/3 = 32

So,

Rachel receives = 32 x 4 = £128

Sanjay receives = 32 x 9 = £288

Hope this helps

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The three sides make a right triangle and you know the base (90) and the height (70)

A = 1/2 bh  or 1/2 x (70)x (90)=   3150 ft²
3 0
3 years ago
Ms. Augustine is playing a game with her class. When a student tells her a number, she uses a rule to determine the new number.
Degger [83]

Answer:

When a student tells her a number, she uses a rule to determ

Step-by-step explanation:

Get the answers ... When a student tells her a number, she uses a rule to determine the new number. Ms. Augustine always uses the same rule. The table below shows some of the results. What would the number be when the student says 8? A. 58. B. 56. C. 54

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2 years ago
What is the largest possible integral value in the domain of the real-valued function
kotegsom [21]

Answer:

Max Value: x = 400

General Formulas and Concepts:

<u>Algebra I</u>

  • Domain is the set of x-values that can be inputted into function f(x)

<u>Calculus</u>

  • Antiderivatives
  • Integral Property: \int {cf(x)} \, dx = c\int {f(x)} \, dx
  • Integration Method: U-Substitution
  • [Integration] Reverse Power Rule: \int {x^n} \, dx = \frac{x^{n+1}}{n+1} + C

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = \frac{1}{\sqrt{800-2x} }

<u>Step 2: Identify Variables</u>

<em>Using U-Substitution, we set variables in order to integrate.</em>

u = 800-2x\\du = -2dx

<u>Step 3: Integrate</u>

  1. Define:                                                                                                            \int {f(x)} \, dx
  2. Substitute:                                                                                         \int {\frac{1}{\sqrt{800-2x} } } \, dx
  3. [Integral] Int Property:                                                                                     -\frac{1}{2} \int {\frac{-2}{\sqrt{800-2x} } } \, dx
  4. [Integral] U-Sub:                                                                                           -\frac{1}{2} \int {\frac{1}{\sqrt{u} } } \, du
  5. [Integral] Rewrite:                                                                                          -\frac{1}{2} \int {u^{-\frac{1}{2} }} \, du
  6. [Integral - Evaluate] Reverse Power Rule:                                                 -\frac{1}{2}(2\sqrt{u}) + C
  7. Simplify:                                                                                                         -\sqrt{u} + C
  8. Back-Substitute:                                                                                            -\sqrt{800-2x} + C
  9. Factor:                                                                                                           -\sqrt{-2(x - 400)} + C

<u>Step 4: Identify Domain</u>

We know from a real number line that we cannot have imaginary numbers. Therefore, we cannot have any negatives under the square root.

Our domain for our integrated function would then have to be (-∞, 400]. Anything past 400 would give us an imaginary number.

7 0
3 years ago
Yvonne wants to cover the back of her smartphone with a decorative pattern. If the phone's length is 1/2 foot and width is 1/6 f
allochka39001 [22]

Answer:

1/12 square foot

Step-by-step explanation:

Area of the pattern = LEngth * Width

Given the following

Length = 1/2 foot

Width = 1/6 foot

Area of the pattern = 1/2 * 1/6

Area of the pattern  =1/12 square foot

Hence the area that the decorative pattern will cover will be 1/12 square foot

4 0
2 years ago
Devon records 4 hours of reality shows on her DVR she records comedy shows for 3/8 of that amount of time. Devon watches all the
Alenkinab [10]

The number of half-hour sittings needed to watch all the shows by Devon is 11

<u>Solution:</u>

Given, Devon records 4 hours of reality shows on her DVR  

she records comedy shows for 3/8 of that amount of time.  

\rightarrow \frac{3}{8} \text { of } 4 \text { hours } \rightarrow \frac{3}{8} \times 4 \rightarrow \frac{3}{2} \text { hours }

Devon watches all the reality and comedy shows in half-hour sittings.

We have to find the number of half-hour sittings needed to watch all the shows

Now, number of half hour sittings is given as

=\frac{\text { total time of videos }}{\text { time for hlaf hour sitting }}

\begin{array}{l}{=\frac{4 \text { hours for reality shows }+\frac{3}{2} \text { hours for comedy shows }}{\frac{1}{2} \text { hours for each sitting }}} \\\\ {=\frac{4+\frac{3}{2}}{\frac{1}{2}}=\frac{\frac{8+3}{2}}{\frac{1}{2}}=\frac{\frac{11}{2}}{\frac{1}{2}}=\frac{11}{2} \times \frac{2}{1}=11}\end{array}

Hence Devon needs 11 sittings

3 0
3 years ago
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