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serious [3.7K]
2 years ago
14

2 + x + y = × + 2 + y (1 point)

Mathematics
1 answer:
kvv77 [185]2 years ago
6 0

Answer:

yes, it is the same thing which means that it will have an infanite solution

You might be interested in
What is 500 miles decreased by 20%?
kobusy [5.1K]

Answer:

400

Step-by-step explanation:

Percentage decrease = 20% × 500

New value = 500 - Percentage decrease

500 - (20% × 500) =

500 - 20% × 500 =

(1 - 20%) × 500 =

(100% - 20%) × 500 =

80% × 500 =

80 ÷ 100 × 500 =

80 × 500 ÷ 100 =

40,000 ÷ 100 =

400

5 0
3 years ago
A van travels 300 miles on 15 gallons of gas. Find how many gallons the van needs to travel 360 miles. 72 gallons of gas 18 gall
leva [86]

simple first we find the miles per gallon

so 300/15=20 therefor he would only need a extra 3 gallons to go 360 miles so your answer is

B.18

6 0
4 years ago
What is the value of x?​
vladimir1956 [14]

Answer:

Step-by-step explanation:

x + 112 + 133+128+100+120= 720

x + 593 = 720

x = 127

3 0
3 years ago
Carl is on the school track team. To prepare for an upcoming race, he plans to run 217 miles total over the next 31 days. Write
Aloiza [94]

Answer:

m=217 miles/31 days

Step-by-step explanation:

Carl has to run 217 miles in 31 days; to find the number of miles m he needs to run per day, he should divide the number of miles he has to run  (217 miles ) by the  number to days he will run ( 31 days):

m=217\:miles/31\:days =7\:miles/day

\boxed{7\:miles/day}

Carl has to run 7 miles per day. We can confirm this result by multiplying this by 31 days, and we should get 217 miles:

(7miles/day)*31days=217 miles.

4 0
3 years ago
Read 2 more answers
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
4 years ago
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