Nitrogen Radius = 5.8 x 10⁻¹¹ m
Beryllium Radius = 1.12 x 10⁻¹⁰ m
Let's find the quotient of N/Be :
(5.8x10⁻¹¹)/(1.12x10⁻¹⁰). But 10⁻¹¹/10⁻¹⁰ = 10⁽⁻¹¹⁺¹⁰⁾ = 10⁻¹ = 1/10 = 0.1
→ (5.8/1.12).(0.1) = 0.58/1.12 = 0.518.
Conclusion: the radius of Be is almost double than the radius of N
Answer:
Step-by-step explanation:
<u>Composite Function</u>
Given f(x) and g(x) real functions, the composite function named fog(x) is defined as:
For practical purposes, it can be found by substituting g into f.
We have:
Computing the composite function:
Operating:
Operating:
Now evaluate for x=4
Answer:
4
Step-by-step explanation:
Cos ( theta ) = cos 7π/6 = -√3/2
sin ( Theta ) = sin 7π/6 = -1/2
Coordinates of the terminal points are: ( -√3/2, -1/2 )
Answer:
D. No, because the differential equation does not have constant coefficients.
Step-by-step explanation:
The undetermined coefficient method cannot be applied to non homogeneous variables. The differential equation does not have constant variables therefore the method of undetermined superposition can not be applied. To complete a solution of non homogeneous equation the particular solution must be added to the homogeneous equation.
