Answer:
This is proved by ASA congruent rule.
Step-by-step explanation:
Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ
we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.
In ΔAPN and ΔAQL
∠PNA=∠ALQ (∵alternate angles)
AN=AL (∵diagonals of parallelogram bisect each other)
∠PAN=∠LAQ (∵vertically opposite angles)
∴ By ASA rule ΔAPN ≅ ΔAQL
Hence, by CPCT i.e Corresponding parts of congruent triangles PA=AQ
Hence, A is equidistant from LM and KN.
Answer: $9
Step-by-step explanation:
10 percent of 9 or 90 broken into 10 parts is 9 also 90 divided by 10 is 9
Solve using trigonometry
tan(39)=24/b
b=24/tan(39)
so b=29.6
for c…
sin(39)=24/c
c=24/sin(39)
c=38.1
B)1,131.20 would be the answer. 1010x0.14=141.4x8=B