The answer is $6.38 hope this helps
You can write it as: 40,048,000,000
Answer:
Step-by-step explanation:
Answer:
95.69%
Step-by-step explanation:
We have X is the number of parts produced up to (and including) the first slightly defective part. So, X is Geometric (2/92), which would be the following:
P (X => 3) = Summation i = 3, up to infinity of {[(90/92)^(i-1)] * (2/92)}
We replace and solve and we are left with:
P (X => 3) = (2/92) * (90/92)^(3-1) * 1/(1 - 90/92)
P (X => 3) = 0.9569
Which means that the probability that at least 3 parts must be produced until there is a slightly defective part produced is 95.69%
Answer:
Larger groups take less time
Step-by-step explanation: