All categories

1 year ago

Help I need some help due tomorrow

Mathematics

1 answer:

SVETLANKA909090 [29]1 year ago

4 0

Answer:

Angle 1: 141 degrees

Angle 2: 39 degrees

Angle 3: 141 degrees

Step-by-step explanation:

Angle 2 and Angle 4 are equal since they are vertical angles. This means that Angle 2 is equal to 39 degrees.

Angle 1 and Angle 4 add up to 180 degrees. We call these supplementary angles. This means that Angle 1 is equal to 180-39=141 degrees.

Angle 1 and Angle 3 are vertical angles, so Angle 3 is also equal to 141 degrees.

You might be interested in

The diameter and height of this cylinder are equal to the side length, S, of the cube in which the cylinder is inscribed. What i

sammy [17]

Volume = πr²h

Diameter = S

Height = S

Radius = S/2

Volume = π ( s²/4 ) s

1/4 πs³

The required answer is in the option ( A )

Hope helps!

7 0

3 years ago

What is 3%+5%+4565+76+90x6(7+5)?

lawyer [7]

I believe it’s 5,193.0315 I’m not to sure

6 0

3 years ago

Read 2 more answers

A collector's model race car is scaled so that 1 inch on the model equals 6 1/4 feet on the actual car. If the model is 2/3 inch

Alchen [17]

The hight of the real car is 4 1/6 ft.

7 0

3 years ago

Marcus daims that in the expression 3x + 3y, the terms 3x and 3y are like terms because both are variable terms and both have th

kumpel [21]

Answer:

Step-by-step explanation:

3x and 3y are not "like terms," despite having the same coefficient.

Like terms have the same variable. For example, 3x and 2x are like terms, so

3x+2x = 5x

7 0

2 years ago

Water is leaking out of an inverted conical tank at a rate of 6800.0 cubic centimeters per min at the same time that water is be

m_a_m_a [10]

Answer:

6.82 $mt^3/min$

Step-by-step explanation:

By congruence of triangles, the radius r of the cone base when its height is 1 meter satisfies the relation

r/1 = 2.5/6

(See picture attached)

So, r = 0.4166 meters when the water is 1 meter high.

The volume of a cone with radius of the base = R is given by

$V=\frac{\pi R^2h}{3}$

So, the volume of water when it is 1 meter high is

$V=\frac{\pi* 0.(4166)^2}{3}=0.1817\;mt^3$

One minute later, the height of the water is 1 meter + 30 centimeters = 1.30 mt

The radius now satisfies

r/1.3 = 2.5/6

and now the radius of the base is

r = 0.5416 mt

and the new volume of water is $0.3071\;mt^3$

So, the water is raising at a speed of

0.3071-0.1871 = 0.12 $mt^3/min$

This speed equals the difference between the water being pumped and the water leaking,

So,

<em>0.12 = Speed of water being pumped -6.8 </em>

and

Speed of water being pumped = 6.8+0.12 = 6.82 $mt^3/min$

8 0

2 years ago