$81.40-$9.00=$72.40
$72.40/.4 (cents)= 181 minutes
Answer:
Any [a,b] that does NOT include the x-value 3 in it.
Either an [a,b] entirely to the left of 3, or
an [a,b] entirely to the right of 3
Step-by-step explanation:
The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.
Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.
Step-by-step explanation:
If PQRS is a quadrilateral inscribed in a circle, then the opposite angles of the quadrilateral are <u>supplementary</u><u>.</u>
y + 68° = 180° { being opposite angles of cyclic quadrilateral }
y = 180° - 68°
y = 112°
x + 82° = 180° { being opposite angles of cyclic quadrilateral }
x = 180° - 82°
x = 98°
Hope it will help :)❤
Answer:
5x-5x+8=2
Step-by-step explanation:
substitute y with -5+8
