4x + 16 factor out gcf
1 answer:
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Answer:
The object hits the ground 5 seconds after being launched.
Step-by-step explanation:
The height of the object in t seconds after being launched is given by the following equation:
When will the object hit the ground after it is launched?
This is t for which h(t) = 0.
So
Then
This is the launch point
So
The object hits the ground 5 seconds after being launched.
Let y = f(x). By the fundamental theorem of calculus, differentiating f(x) twice yields
y is concave upward wherever f''(x) > 0. The denominator is positive for all real x, so the numerator determines the sign of f''(x). We have 6x + 1 = 0 when x = -1/6, and
• for x ∈ (-∞, -1/6), we have e.g. with x = -1, 6x + 1 = -5 < 0
• for x ∈ (-1/6, ∞), we have e.g. with x = 0, 6x + 1 = 1 > 0
Then y is concave upward on the interval (-1/6, ∞).