Answer:
-5
Step-by-step explanation:
(-3)(5) =-15 +10 =-5
Answer:
the least integer for n is 2
Step-by-step explanation:
We are given;
f(x) = ln(1+x)
centered at x=0
Pn(0.2)
Error < 0.01
We will use the format;
[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01
So;
f(x) = ln(1+x)
First derivative: f'(x) = 1/(x + 1) < 0! = 1
2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1
3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2
4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6
This follows that;
Max|f^(n+1) (c)| < n!
Thus, error is;
(n!/(n + 1)!) × 0.2^(n + 1) < 0.01
This gives;
(1/(n + 1)) × 0.2^(n + 1) < 0.01
Let's try n = 1
(1/(1 + 1)) × 0.2^(1 + 1) = 0.02
This is greater than 0.01 and so it will not work.
Let's try n = 2
(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267
This is less than 0.01.
So,the least integer for n is 2
Answer:
y = - 4x + 16
Step-by-step explanation:
Assuming you require the equation of the line passing through the points.
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (3, 4) and (x₂, y₂ ) = (5, - 4)
m = 
= 
= - 4, thus
y = - 4x + c ← is the partial equation
To find c substitute either of the 2 points into the partial equation
Using (3, 4), then
4 = - 12 + c ⇒ c = 4 + 12 = 16
y = - 4x + 16 ← equation of line
61.26 in^2
Explanation: plug in the formula to get SA=2π1.5^2+2π(1.5)(5)
The answer is C 11 1/4 or 11.25 Cubic inches
