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4 years ago

How do i solve this quadratic equation x²+6x+c

1 answer:

6 0

recall in a perfect square trinomial, the middle term is the tale-tell guy, we know the middle term is the product of 2 and the two other guys without the exponent, so in this case 6x = 2*√x² * √c.

$\bf 6x=2\cdot \sqrt{x^2}\cdot \sqrt{c}\implies 6x=2\sqrt{x^2c}\implies 6x=2x\sqrt{c}\\\\\\\cfrac{6x}{2x}=\sqrt{c}\implies 3=\sqrt{c}\implies 3^2=c\implies 9=c$

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Evaluate -a - 12a 2 for a = -1

Serhud [2]

The answer is -11
You put "-1" in place of all the "a"s and get
-(-1) - 12(-1)^2
-(-1) is just 1, and (-1)^2 is "1"
We are then left with 1-12(1) which is 1-12 which is -11

6 0

3 years ago

Wade borrowed $12,500 from his uncle at 4.5% simple interest to use for travel and repaid the loan in 4 years. How much did he p

natali 33 [55]

12,500 / 100 = 125 125 x 4.5 = 562.5 562.5 x 4 = 2250
2250 + 12,500 = 14,750 He paid back a total of $14,750. Hope this helps :)

7 0

3 years ago

Find the equation of line b described below, in slope-intercept form

Serjik [45]

Given:

Line a is perpendicular to line b .

Line a passes through the points (1,-8) and (9,-12) .

Line b passes through the point (-8, -16).

To find:

The equation of b.

Solution:

Line a passes through the points (1,-8) and (9,-12) . So, slope of line a is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m_a=\dfrac{-12-(-8)}{9-1}$

$m_a=\dfrac{-12+8}{8}$

$m_a=\dfrac{-4}{8}$

$m_a=-\dfrac{1}{2}$

Product of slopes of two perpendicular lines is -1.

$m_a\times a_b=-1$

$-\dfrac{1}{2}\times a_b=-1$

$b=2$

Slope of line b is 2.

If a line passing through a point $(x_1,y_1)$ with slope m, then equation of line is

$y-y_1=m(x-x_1)$

Line b passing through (-8,-16) with slope 2. So, equation of line b is

$y-(-16)=2(x-(-8))$

$y+16=2(x+8)$

$y+16=2x+16$

Subtract 16 from both sides.

$y=2x$

Therefore, the equation of line b is $y=2x$ .

7 0

3 years ago

Pleaseeeee help There was a sample of 200 mg of radioactive substance to start a study. Since then, the sample has decayed by 4.

m_a_m_a [10]

Y=200 (1-0.044)^t
.................

8 0

3 years ago

Over the first five years of owning her car, Gina drove about 12,200 miles the first year, 16,211 miles the second year, 12,050

weeeeeb [17]

(12,200 + 16,211 + 12,050 + 11,350 + 13,325) / 5 = 65136/5 =
13027.2 <== this is the mean (average)

11,350 , 12,050 , 12,200 , 13,325, 16,211
median (middle number) = 12,200

there is no mode...a mode is a number that appears most often...all the numbers appear once in this data.

4 0

4 years ago

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