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MArishka [77]
3 years ago
8

How do i solve this quadratic equation x²+6x+c

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

recall in a perfect square trinomial, the middle term is the tale-tell guy, we know the middle term is the product of 2 and the two other guys without the exponent, so in this case 6x = 2*√x² * √c.


\bf 6x=2\cdot \sqrt{x^2}\cdot \sqrt{c}\implies 6x=2\sqrt{x^2c}\implies 6x=2x\sqrt{c}\\\\\\\cfrac{6x}{2x}=\sqrt{c}\implies 3=\sqrt{c}\implies 3^2=c\implies 9=c

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Andrew [12]
The answer is A) y=6x - 11
5 0
3 years ago
Jen Butler has been pricing​ Speed-Pass train fares for a group trip to New York. Three adults and four children must pay $ 132.
laiz [17]
Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
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then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
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subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
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or if you decide to use the other equation:
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3 years ago
Which of the following linear systems has a solution <br> (5,0)<br> SOMEONE PLS HELPPP
Korvikt [17]

Answer:

D

Step-by-step explanation:

out of the choices

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3x+2y=-10

B) x+4y=3

2x+5y=3

C) 2x+3y=5

x-4y=-14

D) 3x+4y=15

x+y=5

only the system in D has a solution of x=5 and y=0

solve by substitution x+y=5 so x=5-y

plug into the other equation so 3(5-y)+4y=15

distribute 15-3y+4y=15 then minus 15 on both sides and combine like terms

so y=0 then put that value back into the other equation

so x+y=5 equals x+0=5 so x=5 this means the solution to the system of equations is the point (5,0)

Hope this helps! :)

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2 years ago
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