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Troyanec [42]
2 years ago
10

Please help I’ll mark you as brainliest if correct!

Mathematics
2 answers:
schepotkina [342]2 years ago
6 0
Increases by +2
Its arithmetic
Sixth number would be 17+2=19
Seventh is 19+2=21
Eighth is 21+2=23

Natalija [7]2 years ago
6 0

Answer: 19, 21, 23

Step-by-step explanation:

is it C that you need to solve?


For C, we can see that each number is going up by 2 to get to the next number, so we can assume that the other 3 numbers follow the same pattern.

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Iam stuck on this quiz and I need help!!
olya-2409 [2.1K]

Answer:

I think it is 3?

Step-by-step explanation:

3,  -2 ≤ 0

-5,  0 < -2 ≤ 5

3, -2 > 5

The second two lines do not hold true, as -2 is less than 0 and 5, not greater. The only that is true is the first one, but I am not sure that is how you do it.1

3 0
3 years ago
Help with this math homework
Ugo [173]

Answer: Ok for the first two they are true.

Step-by-step explanation: So how you would do this is simple, so for # 2 2x-5=11 (x) represents a number and you have to find it. So For this one put an eight in the x's place and that makes 2(8)-5=11 so when you see 2x that mean 2 times what ever x is. so 2x8=16, 16-5 =11.

6 0
3 years ago
Which is the angle measure represented by 1.5 rotations counterclockwise
alexgriva [62]
<span>One rotation is equal to 360 degrees, so 1.5 rotations would be 540 degrees. </span>
7 0
3 years ago
Read 2 more answers
A force of 3 pounds is required to hold a spring stretched 0.6 feet beyond its natural length. how much work (in foot-pounds) is
ioda

The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound

<h3>Data obtained from the question</h3>

From the question given above, the following data were obtained:

  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Work done (Wd) =?

<h3>How to determine the spring constant</h3>
  • Force (F) = 3 pounds
  • Extension (e) = 0.6 feet
  • Spring constant (K) =?

F = Ke

Divide both sides by e

K = F/ e

K = 3 / 0.6

K = 5 pound/foot

Thus, the spring constant of the spring is 5 pound/foot

<h3>How to determine the work done</h3>
  • Spring constant (K) = 5 pound/foot
  • Extention (e) = 0.7 feet
  • Work done (Wd) =?

Wd = ½Ke²

Wd = ½ × 5 × 0.7²

Wd = 2.5 × 0.49

Wd = 1.23 foot-pound

Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound

Learn more about spring constant:

brainly.com/question/9199238

#SPJ1

5 0
2 years ago
Factor completely x2 − 12x +36
ivolga24 [154]

Answer:

(x−6)(x−6)

Step-by-step explanation:

MathPapa algebra calculator, thank me later

8 0
3 years ago
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