Answer:
f(x)=19x - 7x
Step-by-step explanation:
I am a high schooler as well and was working on this problem as well. I can't say I'm right or wrong because I didn't have a grade on it yet. I believe the answer is f(x)=19x - 7x. The Lines don't have a given value, so I chose the values 12 for Line A and 7 for Line B. I believe the answer is this because Line A would produce 12 bags each day and 3 of them would not be useable, leaving you with 9. Line B would produce 7 and 4 of them would be unusable, leaving you with 3. Line A produces 9 per day while Line B produces 3, and that would check off the part that says, "Line A produces 3 times as many bags as Line B each day." Throughout the problem, it talks about how many bags can each line produces each day, and the sentence talks about that specifically as well. So, the function must be about the amount of bags produced per day. x would represent the number of days that the Lines have been working. 19 is the total amount of bags that was produced in a day. 7 represents the total amount of bags that are unusable. Though I may be wrong, I hope this might help you come to a conculsion of your own.
Answer:
19 ft = 19/3 yd
Step-by-step explanation:
If 3 ft = 1 yd, then 19 ft = 1 yd * 19/3 ft = 19/3 yd
Answer:
We are given an area and three different widths and we need to determine the corresponding length and perimeter.
The first width that is provided is 4 yards and to get an area of 100 we need to multiply it by 25 yards. This would mean that our length is 25 yards and our perimeter would be 2(l + w) which is 2(25 + 4) = 58 yards.
The second width that is given is 5 yards and in order to get an area of 100 yards we need to multiply by 20 yards. This would mean that our length is 20 yards and our perimeter would be 2(l + w) which is 2(20 + 5) = 50 yards.
The final width that is given is 10 yards and in order to get an area of 100 yards we need to multiply by 10. This would mean that our length is 10 yards and our perimeter would be 2(l + w) which is 2(10 + 10) = 40 yards.
Therefore the field that would require the least amount of fencing (the smallest perimeter) is option C, field #3.
<u><em>Hope this helps!</em></u>
To find t<span>he relative maximum value of the function we need to find where the function has its first derivative equal to 0.
Its first derivative is -7*(2x)/(x^2+5)^2
</span>7*(2x)/(x^2+5)^2 =0 the numerator needs to be eqaul to 0
2x=0
x=0
g(0) = 7/5
The <span>relative maximum value is at the point (0, 7/5).</span>
