<u>(83.9 × 10^12)(2.87 × 10^-³)</u>
3.76 × 10²
<u>(83,900,000,000,000)(0.00287)</u>
376
<u>240,793,000,000</u>
376
640,406,914.9
Answer:
![d=7.8\ g/cm^3](https://tex.z-dn.net/?f=d%3D7.8%5C%20g%2Fcm%5E3)
Step-by-step explanation:
Given that,
The dimensions of a rectangular block = 4 cm x 2 cm x 1.5 cm
Mass, m = 93.6 g
We need to find the density of steel. We know that the density of an object is equal to the mass divided by volume. So,
![d=\dfrac{m}{V}\\\\d=\dfrac{93.6}{4\times 2\times 1.5}\\\\d=7.8\ g/cm^3](https://tex.z-dn.net/?f=d%3D%5Cdfrac%7Bm%7D%7BV%7D%5C%5C%5C%5Cd%3D%5Cdfrac%7B93.6%7D%7B4%5Ctimes%202%5Ctimes%201.5%7D%5C%5C%5C%5Cd%3D7.8%5C%20g%2Fcm%5E3)
So, the density of the steel is
.
Answer:
(
f
+
g
)
(
x
)
=
3
x
2
+
x
+
2
Explanation:
(
f
+
g
)
(
x
)
=
f
(
x
)
+
g
(
x
)
:
(
f
+
g
)
(
x
)
=
3
x
2
−
x
+
5
+
2
x
−
3
Add like terms:
(
f
+
g
)
(
x
)
=
3
x
2
+
(
−
x
+
2
x
)
+
(
5
−
3
)
(
f
+
g
)
(
x
)
=
3
x
2
+
x
+
2
(
f
+
g
)
(
x
)
=
3
x
2
+
x
+
2
Explanation:
(
f
+
g
)
(
x
)
=
f
(
x
)
+
g
(
x
)
:
(
f
+
g
)
(
x
)
=
3
x
2
−
x
+
5
+
2
x
−
3
Add like terms:
(
f
+
g
)
(
x
)
=
3
x
2
+
(
−
x
+
2
x
)
+
(
5
−
3
)
(
f
+
g
)
(
x
)
=
3
x
2
+
x
+
2
(
f
+
g
)
(
x
)
=
3
x
2
+
x
+
2
Explanation:
(
f
+
g
)
(
x
)
=
f
(
x
)
+
g
(
x
)
:
(
f
+
g
)
(
x
)
=
3
x
2
−
x
+
5
+
2
x
−
3
Add like terms:
(
f
+
g
)
(
x
)
=
3
x
2
+
(
−
x
+
2
x
)
+
(
5
−
3
)
(
f
+
g
)
(
x
)
=
3
x
2
+
x
+
2
Step-by-step explanation:
The formula of a distance between two points:
![d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D)
We have the points (-1, 8) and (5, -2). Substitute:
![d=\sqrt{(5-(-1))^2+(-2-8)^2}=\sqrt{6^2+(-10)^2}=\sqrt{36+100}=\sqrt{136}\\\\=\sqrt{4\cdot34}=\sqrt4\cdot\sqrt{34}=\boxed{2\sqrt{34}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%285-%28-1%29%29%5E2%2B%28-2-8%29%5E2%7D%3D%5Csqrt%7B6%5E2%2B%28-10%29%5E2%7D%3D%5Csqrt%7B36%2B100%7D%3D%5Csqrt%7B136%7D%5C%5C%5C%5C%3D%5Csqrt%7B4%5Ccdot34%7D%3D%5Csqrt4%5Ccdot%5Csqrt%7B34%7D%3D%5Cboxed%7B2%5Csqrt%7B34%7D%7D)