The curve given has asymptotes at x=0 and y=0. We wish to move it right 7 units so the asymptote becomes x=7 and down 5 so the asymptote is y=-5
To move a function down 5 units subtract 5 from it. To move it right we subtract 7 from the independent variable (from the x). The new function is y=(3/(x-7))-5
y= (3 over (x-7)) then minus 5
Answer:
3x + y = -5
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Distributive Property
- Equality Properties
<u>Algebra I</u>
Standard Form: Ax + By = C
Point-Slope Form: y - y₁ = m(x - x₁)
- x₁ - x coordinate
- y₁ - y coordinate
- m - slope
Step-by-step explanation:
<u>Step 1: Define</u>
[PS] y - 11 = 3(x - 2)
<u>Step 2: Rewrite</u>
<em>Find Standard Form</em>
- Distribute 3: y - 11 = 3x - 6
- Subtract 3x on both sides: -3x - y - 11 = -6
- Add 11 to both sides: -3x - y = 5
- Factor -1: -1(3x + y) = 5
- Divide -1 on both sides: 3x + y = -5
Answer:
20/3
Step-by-step explanation:
Every nth term takes the form of a + n*d, where a is the first term.
So 7th term = (54 = a + 7d), 13th term = (94 = a + 13d).
equate them both:
94 - 13d = 54 - 7d
40 = 6d
d = 40/6
Zero-Exponent Rule: a0 = 1, this says that anything raised to the zero power is 1. ... Negative Exponent Rule: , this says that negative exponents in the numerator get moved to the denominator and become positive exponents. Negative exponents in the denominator get moved to the numerator and become positive exponents.
