Have to multiply 3 times here. Let's begin by mult (2x^4)/(y^4) by (3x^3y)/(zy^3):
3*2 = 6
y/y^3 = 1/y^2
x^3*x*4 = x^7
z*y^3*y^4 = z*y^7
So, the product is
3x^7*y 3x^7
----------- and this can be reduced once more: ----------- (answer)
z*y^7 z*y^6
The decagon can be divided in 10 equal parts, so if a full rotation is of 360º, a one tenth rotations will be of 360º/10= 36º
So if you rotate the decagon by a multiple of 36º the rotation will be onto itself, i.e. the figure will look as if it wasn't moved.
From the choices given, the angle that will rotate the angle counterclockwise onto himself will be multiple of 36º, the only one is 72º
This figure has 5 lines of symmetry that cross each vertex and 5 lines of symmetry that cross form the midpoint of one side to the midpoint of the oposite side. This is a total of 10 lines of symetry.
So you can reflect the decagon 10 different ways.
The correct choice is C: 36º, 72º, 10, 5
Answer:
Step-by-step explanation:
All we have to do is input the given values of x into the functions.
The first function:
f(x) = x^2 - 5x - 6
f(0) = 0^2 - 5(0) - 6 = 0 - 0 - 6 = -6
f(0) = -6
f(2) = 2^2 - 5(2) - 6 = 4 - 10 - 6 = -12
f(2) = -12
f(-1) = -1^2 - 5(-1) - 6 = 1 + 6 - 6 = 1
f(-1) = 1
f(6) = 6^2 -5(6) - 6 = 36 - 30 - 6 = 0
f(6) = 0
The second function:
f(x) = x^3 - x^2 - 12
f(0) = 0^3 - 0^2 - 12 = 0 - 0 - 12 = -12
f(0) = -12
f(2) = 2^3 - 2^2 - 12 = 8 - 4 - 12 = -8
f(2) = -8
f(-1) = -1^3 - (-1)^2 - 12 = -1 - 1 - 12 = -14
f(-1) = -14
f(6) = 6^3 - 6^2 - 12 = 216 - 36 - 12 = 168
f(6) = 168
The third function:
f(x) = 5 * 2^x
f(0) = 5 * 2^0 = 5 * 1 = 5
f(0) = 5
f(2) = 5 * 2^2 = 5 * 4 = 20
f(2) = 20
f(-1) = 5 * 2^-1 = 5 * 0.5 = 2.5
f(-1) = 2.5
f(6) = 5 * 2^6 = 5 * 64 = 320
f(6) = 320
3 kilometers is equal to 3000 meters
Distance of a ground is 300 meters sou need to run 10 rounds around thefield
