Answer:
3.48cm³ (approximated)
Step-by-step explanation:
The maximum water that bowl can hold = The volume of the bowl

Radius is half of diameter.
<u>Given</u> -
<em>From</em><em> </em><em>the</em><em> </em><em>given</em><em> </em><em>data</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>derive </em><em>that</em><em> </em><em>the</em><em> </em><em>radius</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>hemispheri</em><em>cal</em><em> </em><em>bowl</em><em> </em><em>is</em><em> </em><em>5</em><em>c</em><em>m</em><em> </em><em>(</em><em>1</em><em>0</em><em>/</em><em>2</em><em>)</em>
Putting the known values into the formula to get the value of the volume of bowl :

= 3.48888cm³
= 3.48cm³
Answer:
the answer is D.
Step-by-step explanation:
.............
Answer:
c. 20,000cm
Step-by-step explanation:
from is house to the park is 100m
from the park back to his house is another 100m
100m+100m=200m
1m = 100cm
200m = xcm
cross multiply
xcm = 200×100
xcm= 20,000cm
Answer:
After simplifying, the exponent of x is 33 and the exponent of y is 0
Step-by-step explanation:
For us to simplify, we bring the x base together and the y base together
Recall from the law of indices;
x^a/x^b = x^(a-b)
and x^a * x^b = x^(a + b)
We shall be applying these here
Let us bring the x terms together
we have these as;
x^8/x^14 * 1/x^-39 = x^( 8 - 14 -(-39))
= x^(8 + 39-14) = x^33
for y, we have it that;
y^-26/y^-5 * 1/y^-21
= y^(-26 -(-5) - (-21)
= y^-26 + 5 + 21 = y^0