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3 years ago

Experimental Probability of Simple Events

1 answer:

5 0

A simple event is an event where all possible outcomes are equally likely to occur. ...A set of all possible outcomes of an event is called sample space, usually represented as 'S' with curly braces { }. ...This is called Experimental Probability – probability derived from a series of trials, or experiments.

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Pleaseeeeeee helpppppppp meeeee

nirvana33 [79]

All are relations except for relation 3

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2 years ago

Click here What is the average rate of change for this exponential function for the interval from x=2 to x = 4? 15 10 -5 5 10 O

Triss [41]

Answer:

c. 6

Step-by-step explanation:

Given

See attachment for graph

Required

Average rate of change

This is calculated as:

$Rate = \frac{f(b) - f(a)}{b - a}$

Where

$(a,b) = (2,4)$

So, we have:

$Rate = \frac{f(4) - f(2)}{4 - 2}$

$Rate = \frac{f(4) - f(2)}{2}$

Using the attached graph, we have:

$f(2) = 4$

$f(4) = 16$

So, we have:

$Rate = \frac{16- 4}{2}$

$Rate = \frac{12}{2}$

$Rate = 6$

4 0

2 years ago

Find the GCF of the terms of the polynomial. 30x3 + 16x5 a. x3 b. 2x3 c. 2x5 d. 16x

Vladimir79 [104]

You can take out 2x^3 from both terms making it
2x^3 (15+8x^2)
Answer is B

3 0

3 years ago

How do I do this? *Look at the directions in the photo*

lora16 [44]

Answer:

$Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2$

Step-by-step explanation:

$We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\$

$As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2$

$For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2$

$For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2$

$Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2$

7 0

2 years ago

Convert the angle theta=7/4pi radians to degrees

bagirrra123 [75]

7/4pi multiplied by 180/pi give you about 97 degrees when you calculate it.

7 0

3 years ago