Question

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Answer 1

The equation of a line in slope-intercept form that is perpendicular to the line x - 5y = 20 isy = -5x + c

How to determine the equation of the line?

The line equation is given as:

x - 5y = 20

Rewrite the above equation as

-5y = -x + 20

Divide both sides by -5

y = 0.2x - 4

A linear equation is represented as

y = mx + c

Where m is the slope

This means that the slope of y = 0.2x - 4 is

m = 0.2

The slope of a perpendicular line is

Slope = -1/m

So, we have

m = -1/0.2

Evaluate

m = -5

Substitute m = -5 in y = mx + c

y = -5x + c

Hence, the equation of a line in slope-intercept form that is perpendicular to the line x - 5y = 20 isy = -5x + c

Read more about linear equations at:

brainly.com/question/14323743

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