The equation of a line in slope-intercept form that is perpendicular to the line x - 5y = 20 isy = -5x + c
<h3>How to determine the equation of the line?</h3>
The line equation is given as:
x - 5y = 20
Rewrite the above equation as
-5y = -x + 20
Divide both sides by -5
y = 0.2x - 4
A linear equation is represented as
y = mx + c
Where m is the slope
This means that the slope of y = 0.2x - 4 is
m = 0.2
The slope of a perpendicular line is
Slope = -1/m
So, we have
m = -1/0.2
Evaluate
m = -5
Substitute m = -5 in y = mx + c
y = -5x + c
Hence, the equation of a line in slope-intercept form that is perpendicular to the line x - 5y = 20 isy = -5x + c
Read more about linear equations at:
brainly.com/question/14323743
#SPJ1
