36=2*2*3*3=2²*3²
60=2*2*3*5=2²*3*5
LCM(36,60)=2*2*3*3*5=2²*3²*5=180
The required point-slope form of the equation of the line is y - 5 = -4(x + 1).
Given that, To determine an equation in point-slope form for the line that passes through the point with the given slope. point: (-1, 5) and m=-4.
What is the slope of the line?
The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.
Here,
The point-slope of the equation of the line is given by,
y - y₁ = m(x - x₁)
Put the values in the above equation of the line
y - 5 = -4 (x - (-1))
y - 5 = -4 (x + 1)
Thus, the required point-slope form of the equation of the line is y - 5 = -4(x + 1).
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(-8, -11) because the points are just the opposite sign when reflecting over the x-axis
Answer:
n(a) X n( b) = 6
Step-by-step explanation:
n(a)= 2
n(b) = 3
n(a) X n( b) = 2x3
=6,,
<span>square pyramid</span>
V=b² h/3------------ >12=9*h/3------------ >h=12/3---- >h=4
the answer is h=4 feet