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V125BC [204]
3 years ago
12

Help please I don’t understand

Mathematics
2 answers:
Sphinxa [80]3 years ago
5 0

Answer:

What are the answers

Step-by-step explanation:

mylen [45]3 years ago
3 0
What are the answers
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What is the quotient of these complex numbers?<br><br> (8-6i)/(3-i)
Aleks04 [339]

Answer: z = 6i / (4+3i)

Step-by-step explanation: Rectangular form:

z = 0.72+0.96i

Angle notation (phasor):

z = 1.2 ∠ 53°7'48″

Polar form:

z = 1.2 × (cos 53°7'48″ + i sin 53°7'48″)

Exponential form:

z = 1.2 × ei 0.2951672

Polar coordinates:

r = |z| = 1.2  magnitude (modulus, absolute value)

θ = arg z = 53.1301° = 53°7'48″ = 0.2951672π  angle (argument or phase)

Cartesian coordinates:

Cartesian form of imaginary number: z = 0.72+0.96i

Real part: x = Re z = 0.72

Imaginary part: y = Im z = 0.96

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3 years ago
If y represents a student's age, which inequality shows that you must be older than 14 to try out for the basketball team?
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Step-by-step explanation:

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A2 + B2 = C2:<br> 13 squared plus b2 equals 18 squared. What is the answer? Please show the work.
Taya2010 [7]

Answer:

Solving (13)^2+(b)^2=(18)^2 we get \mathbf{b=\sqrt{155},b=-\sqrt{155}}

Step-by-step explanation:

13 squared plus b2 equals 18 squared. What is the answer?

We can write it as:

(13)^2+(b)^2=(18)^2

Now, solving and find value of b

We know that 13² = 169

and 18² = 324

Putting values:

(13)^2+(b)^2=(18)^2\\169+b^2=324

Subtract 169 on both sides

169+b^2-169=324-169\\b^2=155

Now, taking square root on both sides

\sqrt{b^2}=\sqrt{155}\\b=\pm\sqrt{155}\\b=\sqrt{155},b=-\sqrt{155}

So, solving (13)^2+(b)^2=(18)^2 we get \mathbf{b=\sqrt{155},b=-\sqrt{155}}

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