Say we have objects, and these objects can be put on a page. Each page can only hold up to 30 objects.
1 answer:
Answer:
<u>, where "n" is number of objects per page.</u>
Step-by-step explanation:
<em>The amount of objects each page could hold is given by dividing the amount of objects that you have, by the number of pages. </em>
<em>• Let the number of objects per page be "n".</em>
<em>Then, the equation that gives us the number of objects for each page, in such way that we have an equal amount of objects per page is:</em>
.
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Answer:
C, 6
Step-by-step explanation:
31-13 is 18, 18/3 is 6.
Answer:
t(16s+15)
Step-by-step explanation:
The highest common factor of 16st+15t is t.
t(16s) + t(15)
Factor.
t(16s+15)
I think that u would have to take 14 from 13 and divide that by 2 (I THINK) i am not fully sure though
15.5 15.5 x 2 = 31. hope this helps