Step-by-step explanation:
<u>Calculate the gross earnings:</u>
<u>Health insurance deduction:</u>
<u>Pension deduction:</u>
<u>Total deductions:</u>
- 55.00 + 15.50 + 21.25 + 46.50 + 20.15 = 158.40
<u>Net pay:</u>
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
The area of the top of the table is 28 × 20 = 560 cm2. The area of Patty’s tiles is 8 cm2 each and the area of Jake’s tiles is 9 cm2 each. Patty will need 560 ÷ 8, or 70, tiles. Jake will need 560 ÷ 9, or about 63, tiles. So, Patty will use about 7 more tiles.
Answer:
b = - 3
Step-by-step explanation:
Please see the attachment below of the following work.
Thanks! Can I have BRAINLIEST please?
Hope this helps!