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RUDIKE [14]
2 years ago
15

The incenter of a triangle is the point of concurrency of the angle bisectors. Does a rectangle have an incenter?

Mathematics
1 answer:
Jobisdone [24]2 years ago
5 0

9514 1404 393

Answer:

  if and only if the rectangle is a square

Step-by-step explanation:

The angle bisectors of a rectangle will meet at a single point if, and only if, the rectangle is a square.

In general, a rectangle does not have an incenter.

__

The incircle must be tangent to all sides of the polygon. That cannot be the case unless the rectangle has its length equal to its width. That is, it must be a square.

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Help me on this it is 70 points
sergiy2304 [10]

Answer:

10.4 or 52/5 or 10  2/5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
HELP
cestrela7 [59]

Answer:

9/4

Step-by-step explanation:

2(x - 10) + 4 = -6x + 2

2x - 20 + 4 = -6x + 2

2x - 16 = -6x + 2

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8x = 18

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7 0
3 years ago
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Roger has two golden retrievers, sadie and buddy, buddy weighs 14 pounds more than sadie, if their total wight is 136 pounds, ho
Vlad1618 [11]

Answer:

A) buddy  = sadie + 14

B) buddy + sadie = 136

A) buddy -sadie = 14

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2 * buddy = 150

buddy = 75 pounds

sadie = 61 pounds


Step-by-step explanation:


6 0
3 years ago
Can someone figure out the problem in this image?
erma4kov [3.2K]
Right side:
(1/27)^(2x+10)
=(3^-3)^(2x+10)
= 3^(-6x - 30)

Re-write both sides:
3^(4x-5) = 3^(-6x - 30)

from here, you can solve x 

4x - 5 = -6x - 30
4x + 6x = -30 + 5
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7 0
3 years ago
Suppose you have a right triangle with congruent legs and a hypotenuse that measure (12sqrt(5))/5 What is the length of the smal
anastassius [24]

The length of the smaller leg is 3.79

<h3>How to determine the length of the smaller leg?</h3>

Represent the smaller leg with x.

So, we have:

x^2 + x^2 = ((12\sqrt5)/5)^2 -- Pythagoras theorem

This gives

2x^2 = 144/5

Divide by 2

x^2 = 72/5

This gives

x^2 = 14.4

Take the square root

x = 3.79

Hence, the length of the smaller leg is 3.79

Read more about right triangles at

brainly.com/question/6322314

#SPJ1

4 0
2 years ago
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