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lilavasa [31]
2 years ago
11

Helppppp nowwwww pleaseeeee now I need help with 1,2,3,4

Mathematics
1 answer:
Rama09 [41]2 years ago
6 0
I’m very sorry but I don’t know this answer my pardon by any chance do you know what’s 56x5y-3
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75 percent of the sutdents in a school went on a field trip. If 285 students went on the trip, how any students are in the schoo
natita [175]

Answer:

380

Step-by-step explanation:

285 / x = 75 / 100

Cross multiply 28500 = 75x

Divide by 75  380

8 0
3 years ago
100 POINTS+BRAINLIEST: 8TH GRADE MATH PT 3- Write equations by simplifying polynomials Tyyy
d1i1m1o1n [39]

Answer:

d.  3x + 6 = 26

Step-by-step explanation:

<u>Definitions</u>

  • Integer:  a whole number that can be positive, negative or zero.
    e.g. ..., -3, -2, -1, 0, 1, 2, 3, ...
  • Even number: an integer that is exactly divisible by two.  For example, 2, 4, 6, 8 are all positive even numbers.
  • Consecutive: following one after the other in order.

<u>The sum of three consecutive even integers</u>

Let x be the first even integer.

As there is a <u>difference of 2</u> between <u>consecutive even integers</u>, the next even integer after x will be (x + 2).

Therefore, the next even integer after (x + 2) will be (x + 2) + 2 = (x + 4).

So "the sum of three consecutive even integers is twenty-six" is:

x + (x + 2) + (x + 4) = 26

<u>To solve</u>

⇒ x + (x + 2) + (x + 4) = 26

⇒ x + x + 2 + x + 4 = 26

⇒ 3x + 6 = 26

(Please note that there are no three consecutive even integers that sum to 26, so the problem cannot be solved).

7 0
2 years ago
Read 2 more answers
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
3 years ago
List three measurements
almond37 [142]
1 inch
5 yards
18 miles
5 0
4 years ago
Read 2 more answers
Suppose you observe a star orbiting the galactic center at a speed of 1300 km/skm/s in a circular orbit with a radius of 18 ligh
laila [671]

Answer: 1.1818^37 kg

Step-by-step explanation:

Given that:

Orbit speed = 1300 km/s

Radius (r) = 18 light days

Mass of object the star is orbiting :

Using the relation :

M = rv² / G

Where ; r = Radius in m ; v = velocity in m/s

G = 6.67 * 10^-11 = gravitational constant

18 light days in meters = 4.662 * 10^14 m

v = 1300km/s to m/s

v = (1300 * 1000)m /s = 1300000 m/s = 1.3 * 10^6 m/s

Hence ;

M = (4.662 * 10^14 * (1.3 * 10^6)^2 / (2/3) * 10^-10

M = (4.662 * 10^14) * (1.69 * 10^12) / (2/3) *10^-10

M = (7.87878 * 10^26) / 6.67 * 10^-11

= 1.1818^37 kg

7 0
3 years ago
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