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Sunny_sXe [5.5K]
2 years ago
8

if there are 20 questions on a test and I get 45% on the test how much is each question worth percent wise??

Mathematics
1 answer:
kompoz [17]2 years ago
3 0
It’s most likely a D
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Simplify in fraction form<br> 60a+64≥80a−92
lukranit [14]

Answer:

a≤39/5

Step-by-steep explanation:

60a+64≥80a−92

Step 1: Subtract 80a from both sides.

60a+64≥80a−92

-80a       -80a

−20a+64≥−92

Step 2: Subtract 64 from both sides.

−20a+64≥−92

         -64   -64

−20a≥−156

Step 3: Divide both sides by -20.

−20a≥−156

a≤39/5

5 0
3 years ago
Write an equation of the line in slope -intercept form ( due today!)
Sati [7]

Answer: The answer would be y=1/3x-3

4 0
3 years ago
R is between q and s. if rs=47 and qs =83.8 find qr
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3 years ago
Over which interval is the graph of f(x) = –x2 + 3x + 8 increasing?
vivado [14]
Hello there!

To find the increasing intervals for this graph just based on the equation, we should find the turning points first.

Take the derivative of f(x)...
f(x)=-x²+3x+8
f'(x)=-2x+3

Set f'(x) equal to 0...
0=-2x+3
-3=-2x
3/2=x

This means that the x-value of our turning point is 3/2. Now we need to analyze the equation to figure out the end behavior of this graph as x approaches infinity and negative infinity.
Since the leading coefficient is -1, as x approaches ∞, f(x) approaches -∞ Because the exponent of the leading term is even, the end behavior of f(x) as x approaches -∞ is also -∞.

This means that the interval by which this parabola is increasing is...
(-∞,3/2)

PLEASE DON'T include 3/2 on the increasing interval because it's a turning point. The slope of the tangent line to the turning point is 0 so the graph isn't increasing OR decreasing at this point.

I really hope this helps!
Best wishes :)
7 0
3 years ago
Read 2 more answers
The circumference of a circular mat is 13π feet. What is the area, in square feet, of the mat? Express your answer in terms of π
qaws [65]

\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=13\pi \end{cases}\implies 13\pi =2\pi r\implies \cfrac{13\pi }{2\pi }=r\implies \boxed{\cfrac{13}{2}=r} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \qquad \implies A=\pi \left(\cfrac{13}{2} \right)^2\implies A=\pi \left( \cfrac{13^2}{2^2} \right)\implies A=\cfrac{169}{4}\pi

6 0
3 years ago
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