Answer:
<em>If statement(1) holds true, it is correct that </em>
<em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em>
<em> is an integer.</em>
<em></em>
Step-by-step explanation:
Given two positive integers
and
.
To check whether
is an integer:
Condition (1):
Every factor of
is also a factor of
.

Let us consider an example:

which is an integer.
Actually, in this situation
is a factor of
.
Condition 2:
Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.
(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)
Let


which is not an integer.
So, the answer is:
<em>If statement(1) holds true, it is correct that </em>
<em> is an integer.</em>
<em>If statement(2) holds true, it is not necessarily correct that </em>
<em> is an integer.</em>
<em></em>
The answer is linked below
Saw the image.
Given:
Whole wall is 13 2/3 ft by 25ft
4 menus (gray areas) with measurements of 6 ft wide and 7 1/2 ft tall.
Convert mixed fractions into improper fractions.
13 2/3 ft = ((13*3)+2)/3 = 41/3
Area of the Wall = 41/3 ft * 25 ft = (41*25)/3 = 1025/3 ft² = 341 2/3 ft²
7 1/2 ft = ((7*2)+1)/2 = 15/2
Area of the menu = 15/2 ft * 6 ft = (15*6)/2 = 90/2 = 45 ft²
45 ft² x 4 menus = 180 ft²
Area of wall space not covered by the chalkboard paint:
A = 341 2/3 ft² - 180 ft² = 161 2/3 ft²
Answer:
22cm,24cm,24cm
Step-by-step explanation:
Let us call one of the other sides x
the shortest side = 2x-26
in an isosceles, 2 sides are equal (x in this case)
so we now have sides of x,x and 2x-26
form an eqution from this.
4x-26=70
4x=96
x=24
24 x 2 = 48 - 26 = 22
thus, the shortest side is 22cm and the other sides are both 24cm
George's financial outcome was $70. He bought it for $50, and then he sold it for $60 in return. He bought it for $70 again, so subtract 60-70= -10. He then sold it for $80 which he gained so -10 + 80 = $70.