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1 year ago

What is the angle between the given vector and the positive direction of the x-axis?

Mathematics

1 answer:

jeka57 [31]1 year ago

6 0

The angle is 75.52 degrees

If there is a vector with the form a i + b j, the cosine of the angle between the given vector and the positive direction of the x - axis is calculated as:

cos θ = $a/\sqrt{a^{2}+b^{2} }$

So, given the vector i+ $\sqrt{15 j$ , the cosine of the angle between the vector and the x-axis is:

cos θ = 0.25

Therefore, the angle θ between the given vector and the positive direction of the x-axis is:

θ = cos-1(0.25) = 75.52

For more information about angles, visit

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Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$

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2 years ago

Given two terms in artimetic sequence find the common difference, the 52 term, and the explicit formula. A15=139 and A30=259

quester [9]

139, 149, 159, 169, 179, 189, 199, 209, 219, 229, 239, 249, 259.

The common difference is 13.

Let n = 52

Let d = common difference

a_52 = 139 + (52 - 1)(13)

a_52 = 139 + (51)(13)

a_52 = 139 + 663

a_52 = 802

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3 years ago

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2 years ago

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Answer:

Yes

Step-by-step explanation:

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