Question

What is the angle between the given vector and the positive direction of the x-axis?

Answer 1

The angle is 75.52 degrees

If there is a vector with the form a i + b j, the cosine of the angle between the given vector and the positive direction of the x - axis is calculated as:

cos θ = $a/\sqrt{a^{2}+b^{2} }$

So, given the vector i+$\sqrt{15 j$, the cosine of the angle between the vector and the x-axis is:

cos θ = 0.25

Therefore, the angle θ between the given vector and the positive direction of the x-axis is:

θ = cos-1(0.25) = 75.52

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