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Liono4ka [1.6K]
3 years ago
9

Drop down 8x – 2 – 5x + 7 =

Mathematics
1 answer:
miss Akunina [59]3 years ago
7 0

Answer:

3x + 5

Step-by-step explanation:

Add like terms together:

8x - 2 - 5x + 7

3x - 2 + 7

3x + 5

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DWAFECGSAD

Step-by-step explanation:

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I need to find weather the ordered pair is a solution of the system of linear equation
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In exercise 3 (2,6) means that x=2 and y=6
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3 years ago
A pizza has a diameter of 12 inches. Each piece has a central angle of radians. What is
Firlakuza [10]

Answer:

The area of one slice of pizza is 18 in²

Step-by-step explanation:

First we have to know that the 360 ​​° representing the circle expressed in radians are expressed as 2π

Now we must calculate the area of ​​the circle

a = π * r²

a = π * (12in)²

a = 144π in²

Now that we have the area of ​​the circumference we multiply it by (π/4) / (2π)

144π in² * (π/4) / (2π) =

144 in² * 1/8 =

18 in²

The area of one slice of pizza is 18 in²

3 0
3 years ago
What is the equation for the line? Enter your answer in the box
Ipatiy [6.2K]

y=-1/2x-4

I could be wrong. Not my strong subject.

-Seth

4 0
3 years ago
PLEASE HELP ME I BEG I WILL GIVE BRAINLIEST
ohaa [14]

Answer:

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

Step-by-step explanation:

7 0
3 years ago
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