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ArbitrLikvidat [17]
3 years ago
10

The cumulative frequency diagram shows the times taken by the members of two different clubs, The Braineys and The Cleverities,

to complete an intelligence test.
a) Find the median and the interquartile range for the Cleverities

b) State which club, on average, was slowest at completing the test. Give the reason for your answer.

Mathematics
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

a) median= 25 mins

   interquartile range= 19mins

b) the braineys , because the braineys took 32mins on average and the cleverites took 25 mins on average which is 7 minutes more.

Step-by-step explanation:

a) find the median by going across the middle of the cumulative frequency (in this case, 40) until it hits the line (the cleverites) and move down to see the time in minutes. 25 mins.

to find the interquartile range, first find the lower quartile. So find the half of the median, or the quarter of the cumulative frequency ( 20) and go across until it hits the line and look down from that point to find the time ( 15 mins). Then, find the upper quartile by finding 3/4 or half+quarter of the cumulative frequency (60) and do the same with the line (34mins)

the interquartile is upper quartile - lower quartile  

34-15= 19 mins

interquartile= 19 mins.

b) the average is the same as the median, so find the median for the cleverites and the median for the braineys, which is 25 mins and 32 mins, therefore the braineys took longer, thus was the slowest at completing the test on average.

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An island is 1 mi due north of its closest point along a straight shoreline. A visitor is staying at a cabin on the shore that i
Elanso [62]

Answer:

The visitor should run approximately 14.96 mile to minimize the time it takes to reach the island

Step-by-step explanation:

From the question, we have;

The distance of the island from the shoreline = 1 mile

The distance the person is staying from the point on the shoreline = 15 mile

The rate at which the visitor runs = 6 mph

The rate at which the visitor swims = 2.5 mph

Let 'x' represent the distance the person runs, we have;

The distance to swim = \sqrt{(15-x)^2+1^2}

The total time, 't', is given as follows;

t = \dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}

The minimum value of 't' is found by differentiating with an online tool, as follows;

\dfrac{dt}{dx}  = \dfrac{d\left(\dfrac{x}{6} +\dfrac{\sqrt{(15-x)^2+1^2}}{2.5}\right)}{dx} =  \dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} }

At the maximum/minimum point, we have;

\dfrac{1}{6} -\dfrac{6 - 0.4\cdot x}{\sqrt{x^2-30\cdot x +226} } = 0

Simplifying, with a graphing calculator, we get;

-4.72·x² + 142·x - 1,070 = 0

From which we also get x ≈ 15.04 and x ≈ 0.64956

x ≈ 15.04 mile

Therefore, given that 15.04 mi is 0.04 mi after the point, the distance he should run = 15 mi - 0.04 mi ≈ 14.96 mi

t = \dfrac{14.96}{6} +\dfrac{\sqrt{(15-14.96)^2+1^2}}{2.5} \approx 2..89

Therefore, the distance to run, x ≈ 14.96 mile

6 0
3 years ago
-1/2x=-10<br><img src="https://tex.z-dn.net/?f=%20-%201%20%5Cdiv%202x%20%3D%20%20-%2010%20" id="TexFormula1" title=" - 1 \div 2x
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Answer:

x= 1/20

Step-by-step explanation:

-1/2x = -10

multiply by 2x on each side

2x(-1/2x) = -10*2x

-1 = -20x

divide by -20

-1/-20 = -20x/-20

1/20 =x

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2 years ago
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he owner of a local supermarket wants to estimate the difference between the average number of gallons of milk sold per day on w
stellarik [79]

Answer:

90% confidence interval is ( -149.114, -62.666   )

Step-by-step explanation:

Given the data in the question;

Sample 1                                Sample 2

x"₁ = 259.23                            x"₂ = 365.12

s₁  = 34.713                              s₂ = 48.297

n₁ = 5                                       n₂ = 10

With 90% confidence interval for μ₁ - μ₂ { using equal variance assumption }

significance level ∝ = 1 - 90% = 1 - 0.90 = 0.1

Since we are to assume that variance are equal and they are know, we will use pooled variance;

Degree of freedom DF = n₁ + n₂ - 2 = 5 + 10 - 2 = 13

Now, pooled estimate of variance will be;

S_p^2 = [ ( n₁ - 1 )s₁² + ( n₂ - 1)s₂² ] / [ ( n₁ - 1 ) + ( n₂ - 1 ) ]

we substitute

S_p^2 = [ ( 5 - 1 )(34.713)² + ( 10 - 1)(48.297)² ] / [ ( 5 - 1 ) + ( 10 - 1 ) ]

S_p^2 = [ ( 4 × 1204.9923) + ( 9 × 2332.6 ) ] / [  4 + 9 ]

S_p^2 = [ 4819.9692 + 20993.4 ] / [  13 ]

S_p^2 = 25813.3692 / 13

S_p^2 = 1985.64378

Now the Standard Error will be;

S_{x1-x2 = √[ ( S_p^2 / n₁ ) + ( S_p^2 / n₂ ) ]

we substitute

S_{x1-x2 = √[ ( 1985.64378 / 5 ) + ( 1985.64378 / 10 ) ]

S_{x1-x2 = √[ 397.128756 + 198.564378 ]

S_{x1-x2 = √595.693134

S_{x1-x2 = 24.4068

Critical Value = t_{\frac{\alpha }{2}, df = t_{0.05, df=13 = 1.771  { t-table }

So,

Margin of Error E =  t_{\frac{\alpha }{2}, df × [ ( S_p^2 / n₁ ) + ( S_p^2 / n₂ ) ]

we substitute

Margin of Error E = 1.771 × 24.4068

Margin of Error E = 43.224

Point Estimate = x₁ - x₂ = 259.23 - 365.12 = -105.89

So, Limits of 90% CI will be; x₁ - x₂ ± E

Lower Limit = x₁ - x₂ - E = -105.89 - 43.224 = -149.114

Upper Limit = x₁ - x₂ - E = -105.89 + 43.224 = -62.666

Therefore, 90% confidence interval is ( -149.114, -62.666   )

3 0
3 years ago
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Leokris [45]

Answer:

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Step-by-step explanation:

Equation of a circle: (x - h)^2 + (y - k)^2 = r^2

(x - 3/4)^2 + (y - 1/2)^2 = r^2

We do not have enough information to find the radius. Were you given another point that lies on the circle?

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