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ArbitrLikvidat [17]
3 years ago
10

The cumulative frequency diagram shows the times taken by the members of two different clubs, The Braineys and The Cleverities,

to complete an intelligence test.
a) Find the median and the interquartile range for the Cleverities

b) State which club, on average, was slowest at completing the test. Give the reason for your answer.

Mathematics
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

a) median= 25 mins

   interquartile range= 19mins

b) the braineys , because the braineys took 32mins on average and the cleverites took 25 mins on average which is 7 minutes more.

Step-by-step explanation:

a) find the median by going across the middle of the cumulative frequency (in this case, 40) until it hits the line (the cleverites) and move down to see the time in minutes. 25 mins.

to find the interquartile range, first find the lower quartile. So find the half of the median, or the quarter of the cumulative frequency ( 20) and go across until it hits the line and look down from that point to find the time ( 15 mins). Then, find the upper quartile by finding 3/4 or half+quarter of the cumulative frequency (60) and do the same with the line (34mins)

the interquartile is upper quartile - lower quartile  

34-15= 19 mins

interquartile= 19 mins.

b) the average is the same as the median, so find the median for the cleverites and the median for the braineys, which is 25 mins and 32 mins, therefore the braineys took longer, thus was the slowest at completing the test on average.

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Please please helpp i will mark brainliest!!! 100 points !! ill mark brainliest if its correct.
Paraphin [41]

Answers and Step-by-step explanations:

1. We need to plug in values of x into the functions f(x) and g(x):

f(2) = 2.5 * 2 - 10.5 = -5.5                         g(2) = 64 * (0.5^2) = 16

f(3) = 2.5 * 3 - 10.5 = -3                            g(3) = 64 * (0.5^3) = 8

f(4) = 2.5 * 4 - 10.5 = -0.5                         g(4) = 64 * (0.5^4) = 4

f(5) = 2.5 * 5 - 10.5 = 2                             g(5) = 64 * (0.5^5) = 2

f(6) = 2.5 * 6 - 10.5 = 4.5                          g(6) = 64 * (0.5^6) = 1

2.

(a) Notice that at 14 on the x-axis, the blue line is above 4. Meanwhile, at 14, the red line is less than 2. Obviously, we can see that if the printed ad revenue was less than 2 and the online ad revenue was greater than 4, that's more than a double, so the lead marketing executive is correct.

(b) The approximate year that the revenues were equal is the place where the lines intersect. It's approximately at Year 7.5.

3.

(a) The Western Beach is clearly decreasing; it is decreasing by 2 ft per year. Meanwhile, the Dunes Beach is clearly increasing; it's increasing by 5 ft per year. (I'm not sure what kinds of "patterns" you're looking for).

(b) Year 11 and 12; this is because here, Western is going from 78 to 76 ft and Dunes is going from 75 to 80, so they'll likely coincide sometime in that time interval.

(c) One thing you can do is to create equations (of the form y = mx + b) for each of the beaches and then set those linear equations equal to each other.

6 0
2 years ago
Read 2 more answers
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