Answer:
-3y (y^2+ 2y-2)
Step-by-step explanation:
i took the test and got this answer
If you're asking about the largest number that can be written with 3 digits in the given base:
• In base 2, the largest number with 3 digits is
111₂ = 1•2² + 1•2¹ + 1•2⁰ = 7
• In base 12, the largest number with 3 digits is
bbb₁₂ = 11•12² + 11•12¹ + 11•12⁰ = 1727
(in base 12, a₁₂ = 10 and b₁₂ = 11)
Hope this helps, although, if you don't understand something, tell me!
Answer:
, n < -16
Step-by-step explanation:
To write this into an inequality you need to recognize keywords. The first keyword is "sum" this means the two numbers must be added; so the first part of the inequality is 4+n. Then, it says the sum is "divided by" 2; this means both numbers must be put over two like 
. Finally, this is "less than" negative. Therefore, this must be an inequality with a sign opening towards -6. So the final answer is .
To solve the inequality isolate the variable. Multiply both sides by 2, so the new inequality is 
. Next, subtract 4 from both sides. The answer is n < -16.
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