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Karo-lina-s [1.5K]
3 years ago
7

Suppose both the mean and median of a distribution are 12. Which of these statements is true about the mode of the distribution?

. . A.The mode is less than 12.. B.There is not enough information to compare the mode.. C.The mode is equal to 12.. D.The mode is greater than 12.
Mathematics
2 answers:
bija089 [108]3 years ago
8 0
The statement that is true about the mode of distribution is there is not enough information to compare the mode. The correct answer is B. 
Setler79 [48]3 years ago
8 0

Answer:

C.The mode is equal to 12

Step-by-step explanation:

We are given that

Mean of a distribution= 12

Median of distribution=12

We have to find the true statement about the mode of the distribution.

We know that the relation between mode, mean and median

Mean-mode=3(mean-median)

Substitute the values in the formula then, we get

12-Mode=3(12-12)=3(0)=0

Mode=12

Hence, the mode of the distribution=12

Answer:C.The mode is equal to 12

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At D.J.s Drink stand Erika ordered a cup of fruit punch made using 1/4 cup of lemonade 1/12 cup of cranberry juice. What fractio
Zepler [3.9K]

The fraction of the orange juice will be 2/3cup.

Why?

Since there is no additional information, let's assume that the fruit punch is made using just three juice fruits, lemonade juice, cranberry juice and the rest is orange juice.

We can calculate the fraction of the orange juice using the following information:

FruitPunch=\frac{1}{4}Lemonade+\frac{1}{12}Cranberry+Orange\\\\1cup=\frac{1}{4}cup+\frac{1}{12}cup+Orange\\\\1cup-(\frac{1}{4}cup+\frac{1}{12}cup)=Orange\\\\1cup-(\frac{12+4}{4*12})=Orange\\\\Orange=1cup-\frac{16}{48}cup=1cup-\frac{1}{3}cup=\frac{3-1}{3}cup=\frac{2}{3}cup

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8 0
4 years ago
NEED MATH HELP QUICK!
Korolek [52]

Answer:

Minimum = 14

Q_1=23

Median = 32

Q_3=49

Maximum = 65

Step-by-step explanation:

<u>Step 1: </u>Put your numbers in ascending order (from smallest to largest). For this particular data set, the order is

14, 18, 28, 29, 32, 44, 48, 50, 65

<u>Step 2:</u> Find the minimum and maximum for your data set. Now that your numbers are in order, this should be easy to spot.

Minimum = 14

Maximum = 65

<u>Step 3: </u>Find the median. The median is the middle number. The middle number in your list is 32, so

Median = 32

<u>Step 4: </u>Place parentheses around the numbers above and below the median.

(14, 18, 28, 29), 32, (44, 48, 50, 65)

<u>Step 5: </u>Find Q1 and Q3. Q1 can be thought of as a median in the lower half of the data, and Q3 can be thought of as a median for the upper half of data.

First quartile

\bf{Q_1=\dfrac{18+28}{2}=\dfrac{46}{2}=23}

Third quartile

\bf{Q_3=\dfrac{48+50}{2}=\dfrac{98}{2}=49}

<u>Step 6:</u> Write down your summary found in the above steps.

Minimum = 14

Q_1=23

Median = 32

Q_3=49

Maximum = 65

5 0
4 years ago
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