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Oduvanchick [21]
2 years ago
9

write a hypotheses about the use of an objects physical charecteristics to determine its density use the format "if then because

" and be sure to answer the lesson question "how can the density of an object be determined?
Physics
1 answer:
JulijaS [17]2 years ago
6 0

i don't know.

Explanation:

because i don't want responde

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kogti [31]

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C. nuclear to electrical

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3 years ago
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lf an object's velocity changes from 25 meters per second to 15 meters per second in 2.0 seconds, the magnitude of the object's
Mila [183]

Answer:

-5 m/s^2

Explanation:

acceleration =  \frac{change \: in \: velocity}{time}  \\  \\  =  \frac{15 - 25}{2}  \\  \\  =  \frac{ - 10}{2}   \\  \\  =  -  5 \: m {s}^{ - 2}  \\  \\ negative \: sign \: represents \: that \:  \\ object \: is \: slowing \: down.

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3 years ago
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Two semiconductors are identical except that one has a band gap of 1.2 eV, while the other has a band gap of 1.1 eV. The room te
solong [7]

To solve this problem it is necessary to apply the relationship given by the intrinsic carrier concentration, in each of the phases.

The intrinsic carrier concentration is the number of electrons in the conduction band or the number of holes in the valence band in intrinsic material. This number of carriers depends on the band gap of the material and on the temperature of the material.

In general, this can be written mathematically as

\eta_i = \sqrt{N_cN_v}e^{-\frac{E_g}{2KT}}

Both are identical semiconductor but the difference is band gap which is:

E_{g1} = 1.1eV

n_{i1} = 1*10^{19}m^{-3}

E_{g2} = 1.2eV

T=300K

The ratio between the two phases are given as:

\frac{\eta_{i1}}{\eta_{i2}} = \frac{e^{-\frac{E_{g1}}{2KT}}}{e^{-\frac{E_{g2}}{2KT}}}

\frac{\eta_{i1}}{\eta_{i2}} = e^{\frac{E_{g2}-E_{g1}}{2KT}}

\frac{\eta_{i1}}{\eta_{i2}} =e^{\frac{(1.2-1.1)(1.6*10^{-19})}{2(1.38*10^{-23})(300)}}

\frac{\eta_{i1}}{\eta_{i2}} =e^{-1.932367}

\frac{\eta_{i1}}{\eta_{i2}} =0.145

Therefore the ratio of intrinsic carrier densities for the two materials at room temperature is 0.145

7 0
4 years ago
Which of these galaxies would you most likely find at the center of a large cluster of galaxies?
Paul [167]

Answer:

a large elliptical galaxy

Explanation:

4 0
2 years ago
A solid nonconducting sphere of radius R carries a charge Q distributed uniformly throughout its volume. At a certain distancer1
Jobisdone [24]

Answer:

The magnitude of the electric field in the second case will be \frac{1}{8} of the electric field in the first case

Explanation:

The electric field at a distance r_1 < R from the center of the sphere is given by

the formula E_1  = \frac{kQr_1}{R^3}  

where R is the radius of the sphere, and, Q is the charge uniformly distributed on the sphere.

It is given that the same charge Q is distributed uniformly throughout a sphere of radius 2R and we have to find the electric field at same distance r_1 from the center.

In the second case the electric field will be given by

E_2 = \frac{kQr_1}{(2R)^3}  = \frac{kQr_1}{8R^3}  =\frac{1}{8}  \frac{kQr_1}{R^3} = \frac{1}{8} E_1

Therefore the magnitude of the electric field in the second case will be \frac{1}{8} of the electric field in the first case.

4 0
4 years ago
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