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gtnhenbr [62]
4 years ago
14

a child is riding a bike at a speed of 0.6m/s with a total kinetic energy of 12.4J.If the mass of the child is 30kg, what is the

mass of the bike?
Physics
2 answers:
Nesterboy [21]4 years ago
8 0
Ek=kinetic energy  (J)
m=mass of object (Kg)
v=speed of object  (m/s)

We have the following formula:

Ek=(1/2)mv²   ⇒ m=2(Ek)/v²

In this case:
m= mass of the child + mass of the bike
m=30 kg + m₁       (m₁=mass of the bike).

We would have to modify our formula like this:

m=2(Ek)/v²
m=30 kg + m₁


30 kg +m₁=2(Ek)/v²
m₁=2(Ek)/v²-30 kg

We have the following data:

v=0.6 m/s
Ek=12.4J
m=30 Kg + m₁

Therefore:

m₁=2(Ek)/v²  - 30 kg
m₁=2(12.4 J)/(0.6 m/s)²  - 30 kg
m₁=24.8 J/(0.36 m²/s²)  -30 kg
m₁=68.89 Kg - 30 kg
m₁=38.89 Kg

Answer: the mass of the bike is 38.89 Kg. 



vova2212 [387]4 years ago
8 0
The mass of the bike is 38.89 Kg. 
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Answer:

1

 t_a  =  13.49 \  s

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 The distance is   D = 55.2 \  m    

Explanation:

From the question we are told that

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Gnerally the equation representing the distance the cheetah needs to move in order to catch the gazelle is

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=>          28.61 t_a = 99.3 +  21.25t_a

=>          7.36 t_a = 99.3

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             7.5 v = D+  7.5u

=>          28.61 * 7.5  = D +  21.25* 7.5

=>          7.36 *  7.5 =D

=>         D = 55.2 \  m        

Hence the for the gazelle to escape the cheetah it must be 55.2 m

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