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3 years ago

8

2..Read the following statements carefully and choose the correct option

1 answer:

Softa [21]3 years ago

6 0

Answer:

statement 1 is correct

2 not sure

Explanation:

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Consider the element carbon. How many electrons can be found in a carbon atom? How many are valence electrons?

Finger [1]

The answer is B: 6; 4. Carbon has four electrons in its outermost shell, which are its valence electrons.

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4 years ago

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4. Anaerobic exercise helps type 2 diabetes.<br> a. True<br> b. False

Ksenya-84 [330]

Answer:

true

Explanation:

b/c anaerobic exercis helps type 2 diabetes

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3 years ago

Describe one behavior that shows that light is a wave

Brilliant_brown [7]

All waves are known to undergo reflection or the bouncing off of an obstacle. Most people are very accustomed to the fact that light waves also undergo reflection. The reflection of light waves off of a mirrored surface results in the formation of an image.

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3 years ago

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Fine grains of beach sand are assumed to be spheres of radius 64.8 µm. These grains are made of silicon dioxide which has a dens

Nutka1998 [239]

Answer:

1) Mass of the grain is $2.9632\times 10^{-9} kg$ .

2) 0.08901 kg of sand would have surface area equal the surface area of the cube.

Explanation:

1) Radius of the grain,r = 64.8 µm = $6.48\times 10^{-5}m$

Volume of the sphere = $\frac{4}{3}\pi r^3$

Volume of the grain of a sand:

$V=\frac{4}{3}\times \pi r^3=\frac{4}{3}\times 3.14\times (6.48\times 10^{-5} m)^3$

$V=1.1397\times 10^{-12} m^3$

Density of a grain of sand = $d=2600 kg/m^3$

Mass of a grain of a sand = M

$d=2600 kg/m^3=\frac{M}{1.1397\times 10^{-12} m^3}$

$M=2.9632\times 10^{-9} kg$

Mass of the grain is $2.9632\times 10^{-9} kg$ .

2) Surface are of sphere: $4\pi r^2$

Surface area of a grain:

$A=4\times 3.14\times (6.48\times 10^{-5}m)^2$

$A=5.2766\times 10^{-8} m^2$

Length of the cube = a = 0.514 m

Total surface area of cube ,A'= $6a^2$

$A'=6\times (0.514 m)^2=1.5851 m^2$

let the number grains with area equal to total surface area of cube be x.

$A'=A\times x$

$x=\frac{1.5851 m^2}{5.2766\times 10^{-8} m^2}=3.003\times 10^7$

Volume of x number of grains :V'

$V'=V\times x$

$V= 1.1397\times 10^{-12} m^3\times 3.003\times 10^7$

$V'=3.4236\times 10^{-5} m^3$

Mass of $3.4236\times 10^{-5} m^3$ of sandL:

= $3.4236\times 10^{-5} m^3\times 2600 kg/m^3=0.08901 kg$

0.08901 kg of sand would have surface area equal the surface area of the cube.

8 0

3 years ago

Calculate the initial (from rest) acceleration of a proton in a 5.00 x 10^6 N/C electric field (such as created by a research Va

julsineya [31]

Answer:

Acceleration of the proton will be equal to $4.79\times 10^{14}m/sec^2$

Explanation:

We have given electric field $E=5\times 10^6N/C$

Mass of proton is equal to $m=1.67\times 10^{-27}kg$

And charge on proton is equal to $e=1.6\times 10^{-19}C$

Electrostatic force will be responsible for the motion of proton

Electrostatic force will be equal to $F=qE=1.6\times 10^{-19}\times 5\times 10^6=8\times 10^{-13}N$

According to newton law force on the proton will be equal to F = ma, here m is mass of proton and a is acceleration

This newton force will be equal to electrostatic force

So $1.67\times 10^{-27}\times a=8\times 10^{-13}$

$a=4.79\times 10^{14}m/sec^2$

So acceleration of the proton will be equal to $4.79\times 10^{14}m/sec^2$

5 0

3 years ago