Answer:
31.32 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
Let us assume the height of the Disque hall is 50 m
In order to make the jump Superman's initial velocity must be greater than or equal to 31.32 m/s
Answer
given,
mass of the shell = 87 g = 0.087 Kg
speed of the muzzle = 853 m/s
mass of the helicopter = 4410 kg
A burst of 176 shell fired in 2.93 s
resulting average force = ?
momentum of the shell = m v
= 0.087 x 853
= 74.21 kgm/s
momentum of 176 shell is = 176 p
= 176 x 74.21
= 13060.96
momentum of helicopter = - 13060.96 kgm/s
amount of speed reduce a =
a=
a = 2.96 m/s²
velocity = \dfrac{2.96}{2.93}
v = 1.01 m/s
Answer:
Explanation:
Given
Initial velocity of ball
height of window
Using Equation of motion
where u=initial velocity
t=time
a=acceleration
As ball is already is at a height of 20 m so
(b)highest point is obtained at v=0
where
v=final velocity
u=initial velocity
a=acceleration
s=displacement
Highest Point will be
(c)Time taken when the ball hit the ground i.e. at Y=0
impact velocity