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kvasek [131]
2 years ago
6

For this Discussion, follow these three steps:

Mathematics
1 answer:
katen-ka-za [31]2 years ago
7 0

Part 1: "If it rains, then there are clouds"

a) "it rains"

b) "there are clouds"

c) true.

d) "if there are clouds, then it rains"

e) false.

Part 2: "If a number is larger than 5, then the number is larger than 3"

a)  "a number is larger than 5"

b)  "a number is larger than 3"

c) true

d) "If a number is larger than 3, then it is larger than 5"

e) False

Part 3: ""A number is even if and only if it is a multiple of 2""

a) true.

<h3>What is a conditional statement?</h3>

For two propositions P and Q, a conditional statement is:

If P then Q.

Part 1:

A conditional statement is:

"If it rains, then there are clouds"

a) The hypothesis is the first proposition, which is "it rains"

b) The conclusion is the second proposition "there are clouds"

c) The statement seems to be true, as the rain comes from the clouds, so it seems to be true.

d) The converse statement is:

"If Q then P"

In this case, it would be:

"If there are clouds, then it rains"

e) That statement is clearly false, because not always that there are clouds in the sky there is rain.

Part 2.

Another conditional statement could be:

"If a number is larger than 5, then the number is larger than 3"

a) The hypothesis is "a number is larger than 5"

b) The conclusion is "a number is larger than 3"

c) The statement is true because 5 is larger than 3, then if a number is larger than 5 it must be larger than 3.

d) The converse statement is:

"If a number is larger than 3, then it is larger than 5"

e) Which is clearly false, a counterexample is 4, which is larger than 3 but not larger than 5.

Part 3.

A biconditional statement is:

P if and only if Q.

One example is:

"A number is even if and only if it is a multiple of 2"

a) That statement is clearly true, as that is the definition of an even number.

If you want to learn more about conditional statements:

brainly.com/question/18152035

#SPJ1

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Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that \mu = 35000, \sigma = 7000

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

Z = \frac{X - \mu}{\sigma}

-1.88 = \frac{X - 35000}{7000}

X - 35000 = -1.88*7000

X = 21840

The designed life should be of 21,840 vehicle miles.

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