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kvasek [131]
2 years ago
6

For this Discussion, follow these three steps:

Mathematics
1 answer:
katen-ka-za [31]2 years ago
7 0

Part 1: "If it rains, then there are clouds"

a) "it rains"

b) "there are clouds"

c) true.

d) "if there are clouds, then it rains"

e) false.

Part 2: "If a number is larger than 5, then the number is larger than 3"

a)  "a number is larger than 5"

b)  "a number is larger than 3"

c) true

d) "If a number is larger than 3, then it is larger than 5"

e) False

Part 3: ""A number is even if and only if it is a multiple of 2""

a) true.

<h3>What is a conditional statement?</h3>

For two propositions P and Q, a conditional statement is:

If P then Q.

Part 1:

A conditional statement is:

"If it rains, then there are clouds"

a) The hypothesis is the first proposition, which is "it rains"

b) The conclusion is the second proposition "there are clouds"

c) The statement seems to be true, as the rain comes from the clouds, so it seems to be true.

d) The converse statement is:

"If Q then P"

In this case, it would be:

"If there are clouds, then it rains"

e) That statement is clearly false, because not always that there are clouds in the sky there is rain.

Part 2.

Another conditional statement could be:

"If a number is larger than 5, then the number is larger than 3"

a) The hypothesis is "a number is larger than 5"

b) The conclusion is "a number is larger than 3"

c) The statement is true because 5 is larger than 3, then if a number is larger than 5 it must be larger than 3.

d) The converse statement is:

"If a number is larger than 3, then it is larger than 5"

e) Which is clearly false, a counterexample is 4, which is larger than 3 but not larger than 5.

Part 3.

A biconditional statement is:

P if and only if Q.

One example is:

"A number is even if and only if it is a multiple of 2"

a) That statement is clearly true, as that is the definition of an even number.

If you want to learn more about conditional statements:

brainly.com/question/18152035

#SPJ1

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A cake recipe calls for 3/4 cup of flour for every 1/3 teaspoon of baking powder. What is the unit rate of cups per teaspoon?
Aliun [14]

Answer:

i just looked it up and i saw 57 so i think thats it

Step-by-step explanation:

6 0
3 years ago
In 2018, the number of students at The Villages High School was 975 and is increasing at a rate of 2.5% per year. Write and use
avanturin [10]

Answer:

A(t)=975(1.025)^t

In 2025,the number of students at the villages high school=1159

Step-by-step explanation:

We are given that in 2018

Number of students at the villages high school=975

Increasing rate,r=2.5%=0.025

We have to write and use of exponential growth function to project the populating in 2025.

A_0=975,t=0

According to question

Number of students at the villages high School is given by

A(t)=A_0(1+r)^t

Substitute the values

A(t)=975(1+0.025)^t=975(1.025)^t

t=7

Substitute the value

Then, the number of students at the villages high school in 2025

A(7)=975(1.025)^7=1158.96\approx 1159

8 0
2 years ago
Read 2 more answers
Plsss help me I don’t understand!!
inna [77]

Answer:

11

Step-by-step explanation:

in the "score" section all you do is add all them up. And because there is a negative for ALL the numbers, all you do is add a negative after you add all the SCORES

6 0
3 years ago
A cement walkway of uniform width has been built around an in-ground rectangular pool. the area of the walkway is 1344 square fe
Elza [17]

Answer:

6 feet.

Step-by-step explanation:

Dimensions of the Pool =80 feet long by 20 feet wide

Area of the walkway =1344 square feet.

If the width of the walkway=w

  • Length of the Larger Rectangle =80+2w
  • Width of the Larger Rectangle =20+2w

Area of the Walkway =Area of the Larger Rectangle - Area of the Pool

1344=(80+2w)(20+2w)-(80*20)\\1344=80*20+160w+40w+4w^2-80*20\\4w^2+200w=1344\\4w^2+200w-1344=0\\We factorize\\4(w^2+50w-336)=0\\4(w^2-6w+56w-336)=0\\w(w-6)+56(w-6)=0\\(w-6)(w+56)=0\\w-6=0$ or $ w+56=0\\w=6$ ft or $ w=-56$ \\Therefore, the width of the walkway , w=6 feet.

6 0
2 years ago
Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the
zlopas [31]

Answer:

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}

\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

3 0
3 years ago
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