All categories

3 years ago

Find (210^4)-(310^3)

Mathematics

1 answer:

Paul [167]3 years ago

4 0

Answer:

1.7*10^4 in scientific notation and 17000 in expanded form

Step-by-step explanation:

You might be interested in

help please! I must solve using descartes law of signs or rational root theorem. show all steps please thanks!

wel

Answer:

x=2 or x=3

Step-by-step explanation:

x^4 - 5x^3 + 7x^2 - 5x + 6 = 0

Step 1=Factor left side of equation.

(x-2) (x-3) (x^2 + 1) = 0

Step 2=Set factors equal to 0.

x-2 = 0 or x-3 = 0 or x^2 + 1 = 0.

Answer:x=2 or x=3

4 0

2 years ago

Differentiate the function. f(x) = sin(9 ln(x))

gayaneshka [121]

Answer: $f'(x)=\dfrac{9\cos(9\ln (x))}{x}$ .

Step-by-step explanation:

The given function is

$f(x)=\sin(9\ln (x))$

Using chain rule differentiate w.r.t. x.

$f'(x)=\cos(9\ln (x))\dfrac{d}{dx}(9\ln (x))$ $\left[\because \dfrac{d}{dx}\sin x=\cos x\right]$

$f'(x)=\cos(9\ln (x))\left[9\dfrac{d}{dx}(\ln (x))\right]$

$f'(x)=\cos(9\ln (x))\left[9\times \dfrac{1}{x}\right]$ $\left[\because \dfrac{d}{dx}\ln x=\dfrac{1}{x}\right]$

$f'(x)=\dfrac{9\cos(9\ln (x))}{x}$

Therefore, $f'(x)=\dfrac{9\cos(9\ln (x))}{x}$ .

5 0

3 years ago

Edgar's friends like the way he makes slime. He can make 5 different batches of slime an hour. Write an equation to model this s

Genrish500 [490]

5 slimes an hour is 1 slime every 20 minutes.

1 Slime: 20 Minutes

4 0

2 years ago

An article in American Demographics claims that more than twice as many shoppers are out shopping on the weekends that during th

Monica [59]

Answer:

0.3085,0.2417,0.0045

Step-by-step explanation:

Given that X, the amount of money spent at shopping centers between 4 P.M. and 6 P.M. on Sundays has a normal distribution with mean $85 and with a standard deviation of $20.

X is N(85, 20)

To convert into std normal variate we use the following formula

$Z=\frac{x-85}{20}$

a) the probability that he has spent more than $95 at the mall

= $P(X>95) = P(Z>0.5)=\\0.5-0.1915\\=0.3085$

b. the probability that he has spent between $95 and $115 at the mall

= $P(95$

c. If two shoppers are randomly selected, what is the probability that both shoppers have spent more than $115 at the mall

=product of two probabilities since independent

= ${P(X>115)}^2\\= P(Z>1.5)*P(Z>1,5)\\= 0.0668^2\\=0.0045$

7 0

3 years ago

Which relations are functions choose all that correct

morpeh [17]

Number 1 and I think 4 not sure but try those .

6 0

3 years ago

Find (2*10^4)-(3*10^3)

Find (210^4)-(310^3)