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1 year ago

AB= 4x + 7 and BC = 20x - 5 AB ~= BC

Mathematics

2 answers:

Mariana [72]1 year ago

8 0

The value of the variable x is 3/4

<h3>What are congruent segments</h3>

Congruent segment are segments with equal or congruent lengths.

From the information given, we have that line AB is approximately equal to line BC. This is represented as;

AB = BC

Where;

AB = 4x + 7
BC = 20x - 7

Now, let's equate the expressions

4x + 7 = 20x - 5

collect like terms

4x - 20x = - 5 - 7

- 16x = - 12

Make 'x' the subject of formula

x = -12/-16

x = 3/4

Thus, the value of the variable x is 3/4

Learn more about line segments here:

brainly.com/question/1388250

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Mnenie [13.5K]1 year ago

6 0

Answer:

3/4

Step-by-step explanation:

Congruent segments have the same length, so:

$AB= BC \\ \\ 4x+7=20x-5 \\ \\ 12=16x \\ \\ x=3/4$

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3 years ago

Solve for q 3 3/4q=30

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3 years ago

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Dominik [7]

Answer:

$\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1$

Step-by-step explanation:

Given:

Center of the ellipse is, $(h,k)=(-4,-3)$

Minor axis length is, $2b=6$

A vertex of the ellipse is at (1, -3)

Now, distance between the center and the vertex is half of the length of the major axis.

Using distance formula for (-4, -3) and (1, -3), we get:

$a=\sqrt{(1+4)^2+(-3+3)^2}=5$

Therefore, the value of half of major axis is, $a=5$ . Also,

$2b=6\\b=\frac{6}{2}=3$

Now, equation of an ellipse with center $(h,k)$ is given as:

$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$

Plug in $h=-4,k=-3,a=5,b=3$ and determine the equation.

$\frac{(x-(-4))^2}{5^2}+\frac{(y-(-3))^2}{3^2}=1\\\\\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1$

Therefore, the equation of the ellipse is:

$\frac{(x+4)^2}{25}+\frac{(y+3)^2}{9}=1$

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2 years ago

The center of a circle is located at (3, 8), and the circle has a radius that is 5 units long. What is the general form of the e

lana [24]

First we write equation that consist coordinates of center and radius. That formula goes like this:
(x-x1)^2 + (y-y1)^2 = r^2

x and y are coordinates on any point on circle
x1 and y1 are coordinates of center of circle.
r is radius of that circle. now we need to express our values for center and radius andf square binoms and see what matches in our options.

(x-3)^2 + (y-8)^2 = 5^2
x^2 + y^2 -6x -16y +48 = 0

The answer is first option.

5 0

3 years ago