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MrMuchimi
3 years ago
13

Which of the following is an example of the associative property?

Mathematics
1 answer:
Bingel [31]3 years ago
8 0

Answer:

A)

Step-by-step explanation:

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Jessica is thinking of a number that rounds to 1,300 for the nearest ten and for the nearest hundred.What number might she be th
Pavel [41]
Hey There!

One of the numbers she might be thinking of could be 1,298, because it rounds to 1,300 in the nearest hundreds, and for the nearest tens. Remember, when a number is greater than 5 you round it to the nearest ten. Same rule applies for the hundreds, but the number has to be in the tens place instead of the ones place.

Have A Brainly Day :)

Send me a message for more help :)
5 0
3 years ago
Which Figure has a line sysmmetry F,H,J,L,R
Makovka662 [10]

Answer:

njnjfsdnjfe

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
george completed 3/5th of work in 9 days with the help of paul he completes remaining work in 4 days.In how many days paul alone
IRINA_888 [86]
If George completed 3/5 of work in 9 days, it means that he needs 3 days to finish 1/5th of the work.

The remaining part is 2/5 because 1-3/5=2/5. 2/5 is also 6/15

From this, how much did George do? in the first 3 days he did 1/5th and then one more day was left, during which he did 1/5/3=1/15th.

So he did in total 1/15+1/5=1/15+3/15=4/15.
this means that Paul did the rest of 6/15, so Paul did 6/15-4/15=2/15.

So we know that he does 2/15 in 4 days, which means that every two days he can do 1/15 of the work

so he would need 15 times 2 days to finish the work - 30 days!
6 0
3 years ago
Someone help and plz make sure it’s right plz! :)
kvv77 [185]

Answer:

-21/4

Step-by-step explanation:

slope = y2-y1/ x2-x1

-18 - 3 / 17-13 = -21/4

4 0
2 years ago
9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9
gladu [14]

Answer:  a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height  = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976

Hence, a) (176.76,172.24), b) 0.976.

8 0
2 years ago
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