Answer:
5a
Step-by-step explanation:
Solution
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We have x
3
−ax
2
+6x−a
Apply remainder theorem
x−a=0
x=a
Put x=a in equation.
(a)
3
−a(a)
2
+6a−a
=a
3
−a
3
+6a−a
=6a−a
=5a
Then reminder is 5a
The answer is any whole number larger than 3
The answer would be 6x/5-16/5
Answer:
k = ln (6/5)
Step-by-step explanation:
for
f(x)=A*exp(kx)+B
since f(0)=1, f(1)=2
f(0)= A*exp(k*0)+B = A+B = 1
f(1) = A*exp(k*1)+B = A*e^k + B = 2
assuming k>0 , the horizontal asymptote H of f(x) is
H= limit f(x) , when x→ (-∞)
when x→ (-∞) , limit f(x) = limit (A*exp(kx)+B) = A* limit [exp(kx)]+B* limit = A*0 + B = B
since
H= B = (-4)
then
A+B = 1 → A=1-B = 1 -(-4) = 5
then
A*e^k + B = 2
5*e^k + (-4) = 2
k = ln (6/5) ,
then our assumption is right and k = ln (6/5)
Answer:
A.
Step-by-step explanation:
1.5m + 6.5q > 100
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