The answer to the above question can be determined as -
Let the point on the left side of P be Q, thus coordinates of Q are (a,1) and point on the right side of P be R, thus coordinates of R will be, (a+4, 1).
Now, it given that, between x coordinates of Q and R is 4, and it can be seen that they are getting divided into half.
So, the x coordinate of P will be - a + i.e. a + 2
<u>Thus, the x coordinate of P will be a +2.</u>
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Answer:
1.60
Step-by-step explanation:
Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.
i.e Area =
So that,
for the inner part of the pipe,
r =
=
= 2.5 feet
Area of the inner part of the pipe =
= 3.14 x
= 19.625
Are of the inner part of the pipe is 19.63 .
Total diameter of the pipe = 5 + 0.2
= 5.2 feet
r =
= 2.6 feet
Area of the pipe =
= 3.14 x
= 21.2264
Area of the pipe is 21.23 .
Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe
= 21.2264 - 19.625
= 1.6014
The cross sectional area of the cement pipe is 1.60 .