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Rudiy27
3 years ago
13

Eight students are competing for a blue, red, and yellow ribbon for their agriculture project. How many different ways are there

to present those ribbons if the order matters?
Mathematics
2 answers:
Len [333]3 years ago
8 0
If the order matters, then we are dealing with permutation. There are 8 students and three colors. This gives us the expression

₈P₃

which is equal to 336.

Therefore, there are 336 different ways.
EleoNora [17]3 years ago
4 0

Answer:

336

Step-by-step explanation:

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To paint a house, a painting company charges a flat rate of $500 for supplies, plus $50 for each hour of labor.
sattari [20]

Answer:

50x20=1000+500= 1500

50x50=2500+500=3000

Step-by-step explanation:

7 0
2 years ago
82. Subtract 12x? + 6y - 3 and 3x? - 9y + 12
balu736 [363]

Answer:

-x^2+15y-15

Answer if it is a ^2

Step-by-step explanation:

2x^2 + 6y - 3 -(3x^2 - 9y + 12)=

2x^2+6y-3-3x^2+9y-12=

-x^2+15y-15

is it a ^2 or a question mark

3 0
3 years ago
4. In ADEF, ZE is a right angle. If the side opposite ZD has a length of 17 and the length of the hypotenuse
Len [333]
The answer would be 2, 41° i think
5 0
2 years ago
Let X and Y be discrete random variables. Let E[X] and var[X] be the expected value and variance, respectively, of a random vari
Ulleksa [173]

Answer:

(a)E[X+Y]=E[X]+E[Y]

(b)Var(X+Y)=Var(X)+Var(Y)

Step-by-step explanation:

Let X and Y be discrete random variables and E(X) and Var(X) are the Expected Values and Variance of X respectively.

(a)We want to show that E[X + Y ] = E[X] + E[Y ].

When we have two random variables instead of one, we consider their joint distribution function.

For a function f(X,Y) of discrete variables X and Y, we can define

E[f(X,Y)]=\sum_{x,y}f(x,y)\cdot P(X=x, Y=y).

Since f(X,Y)=X+Y

E[X+Y]=\sum_{x,y}(x+y)P(X=x,Y=y)\\=\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y).

Let us look at the first of these sums.

\sum_{x,y}xP(X=x,Y=y)\\=\sum_{x}x\sum_{y}P(X=x,Y=y)\\\text{Taking Marginal distribution of x}\\=\sum_{x}xP(X=x)=E[X].

Similarly,

\sum_{x,y}yP(X=x,Y=y)\\=\sum_{y}y\sum_{x}P(X=x,Y=y)\\\text{Taking Marginal distribution of y}\\=\sum_{y}yP(Y=y)=E[Y].

Combining these two gives the formula:

\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y) =E(X)+E(Y)

Therefore:

E[X+Y]=E[X]+E[Y] \text{  as required.}

(b)We  want to show that if X and Y are independent random variables, then:

Var(X+Y)=Var(X)+Var(Y)

By definition of Variance, we have that:

Var(X+Y)=E(X+Y-E[X+Y]^2)

=E[(X-\mu_X  +Y- \mu_Y)^2]\\=E[(X-\mu_X)^2  +(Y- \mu_Y)^2+2(X-\mu_X)(Y- \mu_Y)]\\$Since we have shown that expectation is linear$\\=E(X-\mu_X)^2  +E(Y- \mu_Y)^2+2E(X-\mu_X)(Y- \mu_Y)]\\=E[(X-E(X)]^2  +E[Y- E(Y)]^2+2Cov (X,Y)

Since X and Y are independent, Cov(X,Y)=0

=Var(X)+Var(Y)

Therefore as required:

Var(X+Y)=Var(X)+Var(Y)

7 0
3 years ago
the number of hours h that it takes for ice to malt varies inversely with the temperature t it takes 3hours for a piece of ice t
Reptile [31]

Answer:

Step-by-step explanation:

Formula

h = k/temp

Givens

h = 4 hours

t = 45 degrees

Solution

3 = k / 45                  Multiply both sides by 45

3*45 = k

k = 135

Problem

what happens when h = 4 hours?

h = 4

k = 135

temp = ?

4 = 135 / temp       Multiply both sides by temp

4temp = 135          Divide by 4

temp = 135 / 4

temp = 33.75

Note that as the time went up, the temperature came down

6 0
2 years ago
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