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Aleks04 [339]
1 year ago
13

Alex, Bob and Carl go for a walk every day. If Alex doesn't wear a hat, then Bob wears

Mathematics
1 answer:
bazaltina [42]1 year ago
3 0

Answer:

Carl and Alex are wearing hats.

Step-by-step explanation:

If Bob doesn't isn't wearing a hat, then Carl is, so Carl clearly is wearing a hat.

Now let's look at Alex. If he wasn't wearing a hat, then Bob would be wearing one. (If Alex doesn't wear a hat, then Bob wears

a hat). The logical conclusion is that Alex must be wearing a hat as well.

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Use the function below to find f(4).
Afina-wow [57]

Answer:

F(4)=1/3*4^4

F(4)=256/3

Step-by-step explanation:

4^4=256

(1/3)*(256)=

256/3

Simply replace X with 4

5 0
3 years ago
A scuba diver dove 40 feet below the surface. He swam up 12 feet to see a unique fish. He followed the fish down 8 feet. Then he
Ber [7]

Answer: 9 feet below the surface.

Step-by-step explanation:

The scuba diver starts 40 ft below the surface. We can represent the position of the scuba diver as:

Position = -40ft

Where the negative sign is because it is below the surface of the water, so

"He swam up 12 feet to see a unique fish."

Now we need to add 12ft

Then his new position is:

Position = -40ft + 12 ft = -28ft

"He followed the fish down 8 feet.

Now we need to subtract 8ft

His new position is:

Position = -28ft - 8 ft = -36 ft

"Then he followed the fish up 27 feet."

Now we add another 27 ft.

The final position will be:

Position = -36ft + 27ft = -9ft

Then the final position of the scuba diver is -9ft, that means that he is 9 feet below the surface.

6 0
2 years ago
Find the slope of the line graphed below.
natulia [17]
Good day ^-^///////////

6 0
3 years ago
Read 2 more answers
3 3/8 - 1 1/2 how do you solve e this
ser-zykov [4K]
In exact form it would be 15/8
5 0
3 years ago
Help me asap! I will give you marks
Law Incorporation [45]

Recall the binomial theorem.

(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k

1. The binomial expansion of \left(1+\frac x3\right)^7 is

\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}

Observe that

k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x

k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2

When we multiply these by 8-9x,

• 8 and \frac73 x^2 combine to make \frac{56}3 x^2

• -9x and \frac73 x combine to make -\frac{63}3 x^2 = -21x^2

and the sum of these terms is

\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}

2. The binomial expansion is

\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k

We get the a^6b^2 term when k=2 :

k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2

6 0
1 year ago
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