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amm1812
3 years ago
12

How many different four-digit numbers can be made using the digits 1, 2, 3, 4, 5, 6 if no digit can be used more than once?

Mathematics
1 answer:
Allushta [10]3 years ago
4 0
This is 6P4
the number of permutations of 4 from 6.  6! / 2!

= 6*5*4*3* 2 /  2 = 360
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8/f = 56/105 what is f?
svetlana [45]
8/15 = 56/105

This may be solved using proportion.
a/b = c/d
ad = bc   where cross products are equal.

a = 8
b = f
c  = 56
d = 105

ad = bc
8*105 = f*56
840 = 56f
840/56 = 56f/56
f = 15

56 ÷ 7 = 8
105 ÷ 7 = 15
6 0
3 years ago
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maksim [4K]

Answer:

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Step-by-step explanation:

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