Negative times a Negative = Positive
Positive times a Positive = Positive
Negative times a Positive = Negative
Positive times a Negative = Negative
Option A:
Negative * Positive * Negative * Positive
Negative * Negative * Positive
Positive * Positive
Positive
Option B:
Anything times 0 is 0, this is incorrect.
Option C:
Negative * Negative * Negative * Negative
Positive * Negative * Negative
Negative * Negative
Positive
Option D:
Negative * Positive * Negative * Negative
Negative * Negative * Negative
Positive * Negative
Negative
Therefore your answer is D.
Answer: d 99
Step-by-step explanation:
Answer:
-7x<21
i think, I'm not fully sure what it's asking.
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
X2-Y2
_____
X1 - X1
plug in the numbers
8-3 / 3+7 = 5/2 which simplifies down to 2
<u>ANSWER </u>
and 
<u>EXPLANATION</u>
Given;
and
The augmented matrix of the two linear equation is given by;
![\left[\begin{array}{ccc}4&-12|&-1\\6\:&\:\:\:4|&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-12%7C%26-1%5C%5C6%5C%3A%26%5C%3A%5C%3A%5C%3A4%7C%264%5Cend%7Barray%7D%5Cright%5D)
We now perform row operations;
.
This gives us
![\left[\begin{array}{ccc}1&-3|&\frac{-1}{4}\\6\:&\:\:\:4|&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-3%7C%26%5Cfrac%7B-1%7D%7B4%7D%5C%5C6%5C%3A%26%5C%3A%5C%3A%5C%3A4%7C%264%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}1&-3|&\frac{-1}{4}\\0\:&\:\:\:22|&\frac{11}{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-3%7C%26%5Cfrac%7B-1%7D%7B4%7D%5C%5C0%5C%3A%26%5C%3A%5C%3A%5C%3A22%7C%26%5Cfrac%7B11%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}1&-3|&\frac{-1}{4}\\0\:&\:\:\:1|&\frac{1}{4}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%26-3%7C%26%5Cfrac%7B-1%7D%7B4%7D%5C%5C0%5C%3A%26%5C%3A%5C%3A%5C%3A1%7C%26%5Cfrac%7B1%7D%7B4%7D%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}1&0|&\frac{1}{2}\\0\:&\:\:\:1|&\frac{1}{4}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%7C%26%5Cfrac%7B1%7D%7B2%7D%5C%5C0%5C%3A%26%5C%3A%5C%3A%5C%3A1%7C%26%5Cfrac%7B1%7D%7B4%7D%5Cend%7Barray%7D%5Cright%5D)
Hence and
