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Free_Kalibri [48]
2 years ago
6

Question 7 of 10

Mathematics
1 answer:
Gelneren [198K]2 years ago
5 0

The group of values plugged into the TVM Solver of a graphing calculator that will return the amount of a 25-year loan with an APR of 16.8%, that is paid off with monthly payments of $340 is:

A. N=300; 1%-1.4; PV = PMT=-340; FV=0; P/Y=12; C/Y=12;PMT:END

What is monthly compounding?

Monthly compounding in this case the number of payments would be the number of monthly payments in 25 years, which is 300 monthly payments(i.e. 12*25=300), this means that options B and D are obviously incorrect because number of payments, N is given as 25( 25 years instead of 300 months)

What is monthly interest rate?

The monthly interest is the annual interest rate of 16.8% divided by 12, which is 1.40%, in short, option C is also wrong because I/Y(monthly interest rate) was as shown as an interest rate of 16.8% instead of 1.40%

Overall, the correct option is A, because the number of payments and interest rate were stated correctly, unlike other options that were incorrectly written

Find out about more about TVM Solver notations on:brainly.com/question/14586708

#SPJ1

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No because the cost to ship a video game starts at 4.85 but if it were to start at zero than I would because it consistently adds 39.99.
8 0
3 years ago
For each value of kk specified in parts (a)–(e), plot the set of points in the plane that satisfy the equation
son4ous [18]

Answer:

Seee answer below.

Step-by-step explanation:

a. k = −1

If K=-1 the equation gets this form:

(x^2/-1) -y^2=1

There aren't natural numbers that being negative, adding them, we get 1 as result. So there is no graph for this equation.

b. k = 1

(x^2/1) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

c. k = 2

(x^2/2) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

d. k = 4

(x^2/4) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

e. k = 10

(x^2/10) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

f. k = 25

(x^2/25) -y^2=1

This is the natural form of the equation of an hyperbola. Attached you can find the graph.

g. Describe what happens to the graph of

x2 / k − y2 = 1 as k → [infinity].

As K is increasing the value of X will be tending to 0. So the equation for this will be:

− y^2 = 1.The solution for this is in the domain of the imaginary numbers.

5 0
3 years ago
Cheddar cheese costs $4.25 per pound. Write an equation best represents y, the total cost of x pounds of cheddar cheese and type
choli [55]

Answer:

y=4.25x

Step-by-step explanation:

x will represent the number of pounds of cheddar that you have. so whatever the value of X is, 4.25 would be multiplied by X. This problem does not provide a value for x, but say you had 4 pounds of cheese (x=4), the problem would become y=4.25(4) because you would plug 4 in where x is.

4.25(4)= 17 and therefore Y would equal 17.

8 0
3 years ago
demitri hikes 12 Miles on Wednesday and Thursday the amount of miles he hikes decreases by 25% how many miles did he hike on Thu
aleksandr82 [10.1K]

Answer:

.

Step-by-step explanation:

.

5 0
4 years ago
A company did a quality check on all the packs of trail mix it manufactured. Each pack of trail mix is targeted to weigh 9.25 oz
Tema [17]

Answer:

d. x < 9.02 or x > 9.48 because |x − 9.25| > 0.23

Step-by-step explanation:

Given,

The standard weight of the pack = 9.25 oz,

The pack must weigh within 0.23 oz of the target weight to be accepted.

i.e. if x represents the weight of the pack,

If x > 9.25 oz

then x - 0.925 ≤ 0.23  ......(1)

if x < 9.25

then 9.25 - x ≤ 0.23

⇒ -(x-9.25) ≤ 0.23   .......(2)

From equation (1) and (2),

The accepted range of mass is,

|x-9.25| ≤ 0.23

Hence, the rejected range mass would be,

|x-9.25| > 0.23

⇒ x - 9.25 > 0.23 or -x + 9.25 < 0.23

⇒ x > 0.23 + 9.25 or -x > 0.23 - 9.25

⇒ x > 9.48 or - x > −9.02

⇒ x > 9.48 or  x < 9.02

5 0
3 years ago
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