Yes there are more ounces in 1 ton then there are pounds in 1 ton. 1 ton is made of/ is the equivalent to 2000 pounds. Then to go smaller pounds can be broken into ounces, there are 16 ounces in a pound.
So 1 ton is equal to 2,000 pounds and...
1 ton is equal to 32,000.
So yea there are more ounces in a ton than more pounds in a ton.
![y=\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt](https://tex.z-dn.net/?f=y%3D%5Cdisplaystyle%5Cint_1%5Ex%5Csqrt%7Bt%5E3-1%7D%5C%2C%5Cmathrm%20dt)
By the fundamental theorem of calculus,
![\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm d}{\mathrm dx}\displaystyle\int_1^x\sqrt{t^3-1}\,\mathrm dt=\sqrt{x^3-1}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cdisplaystyle%5Cint_1%5Ex%5Csqrt%7Bt%5E3-1%7D%5C%2C%5Cmathrm%20dt%3D%5Csqrt%7Bx%5E3-1%7D)
Now the arc length over an arbitrary interval
![(a,b)](https://tex.z-dn.net/?f=%28a%2Cb%29)
is
![\displaystyle\int_a^b\sqrt{1+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}\,\mathrm dx=\int_a^b\sqrt{1+x^3-1}\,\mathrm dx=\int_a^bx^{3/2}\,\mathrm dx](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint_a%5Eb%5Csqrt%7B1%2B%5Cleft%28%5Cfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%5Cright%29%5E2%7D%5C%2C%5Cmathrm%20dx%3D%5Cint_a%5Eb%5Csqrt%7B1%2Bx%5E3-1%7D%5C%2C%5Cmathrm%20dx%3D%5Cint_a%5Ebx%5E%7B3%2F2%7D%5C%2C%5Cmathrm%20dx)
But before we compute the integral, first we need to make sure the integrand exists over it.
![x^{3/2}](https://tex.z-dn.net/?f=x%5E%7B3%2F2%7D)
is undefined if
![x](https://tex.z-dn.net/?f=x%3C0)
, so we assume
![a\ge0](https://tex.z-dn.net/?f=a%5Cge0)
and for convenience that
![a](https://tex.z-dn.net/?f=a%3Cb)
. Then
Perímeter of rectangular area= 2(long + width)
Then:
Perimeter =2.(50 m+10 m)=2.(60 m)=120 m
Sol: 50 m x 10 m
The correct answers are B, C and D!
We know that
[volume of a <span>pyramid]=[area of the base]*h/3
</span><span>a) The scale factor of the smaller pyramid to the larger pyramid in simplest form
</span><span>
12/20----------> 3/5
the answer Part a) is 3/5
</span><span>(b) The ratio of the area of the base of the smaller pyramid to the base of the larger pyramid
[</span>The ratio of the area of the base of the smaller pyramid to the base of the larger pyramid]--------> (3/5)²------> 9/25------> 0.36
[volume of a larger pyramid]=8192 cm³
h=20 cm
so
[8192]=[area of the base larger pyramid]*20/3
[area of the base larger pyramid]=8192*3/20------> 1228.80 cm²<span>
</span>[area of the base smaller pyramid]=(3/5)²*1228.80-----> 442.37 cm²
The ratio of the area of the base of the smaller pyramid to the base of the larger pyramid-----------> 442.37/1228.8--------> 0.36
0.36--------> is equal to (3/5)²
the answer part b) is 0.36
<span>(c) Ratio of the volume of the smaller pyramid to the larger
</span>
[Ratio of the volume of the smaller pyramid to the larger]=(3/5)³---> 27/125
27/125------> 0.216
the answer Part c) is 0.216
<span>(d) The volume of the smaller pyramid
[</span>The volume of the smaller pyramid]=0.216*8192------> 1769.47 cm³
<span>
the answer part c) is </span>1769.47 cm³<span>
</span>