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mina [271]
2 years ago
9

Which phase of inferential statistics is sometimes considered to be the most crucial because errors in this phase are the most d

ifficult to correct?
Mathematics
1 answer:
Alex_Xolod [135]2 years ago
7 0

The phase of inferential statistics which is sometimes considered to be the most crucial because errors in this phase are the most difficult to correct is "data gathering".

<h3>What is inferential statistics?</h3>

Inferential statistics are frequently employed to compare treatment group differences.

Some characteristics of inferential statistics are-

  • Inferential statistics compare treatments groups and make conclusions about the greater population of participants using measures from the experiment's sample of subjects.
  • Inferential statistics aids in the development of explanations for a condition or phenomenon.
  • It enables you to draw conclusions on extrapolations, which distinguishes it from descriptive statistics, which simply summarize the information that has been measured.
  • There are numerous varieties of inferential statistics, each with its own set of research design & sample characteristics.
  • To select the correct statistical test of their experiment, researchers should reference the numerous texts about experimental design and statistics.

To know more about the inferential statistics, here

brainly.com/question/4774586

#SPJ4

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A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude
EleoNora [17]

Answer:

a) P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

And we can use the probability mass function and we got:

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369  

And adding we got:

P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061

b) P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182  

c) P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369

P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054

And replacing we got:

P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886

d) E(X) = 20*0.2= 4

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=20, p=0.2)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Part a

We want this probability:

P(X \leq 2)= P(X=0)+P(X=1)+P(X=2)

And we can use the probability mass function and we got:

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369  

And adding we got:

P(X \leq 2)=0.0115+0.0576+0.1369 = 0.2061

Part b

We want this probability:

P(X=4)

And using the probability mass function we got:

P(X=4)=(20C4)(0.2)^4 (1-0.2)^{20-4}=0.2182  

Part c

We want this probability:

P(X>3)

We can use the complement rule and we got:

P(X>3) = 1-P(X \leq 3) = 1- [P(X=0)+P(X=1)+P(X=2)+P(X=3)]

P(X=0)=(20C0)(0.2)^0 (1-0.2)^{20-0}=0.0115  

P(X=1)=(20C1)(0.2)^1 (1-0.2)^{20-1}=0.0576  

P(X=2)=(20C2)(0.2)^2 (1-0.2)^{20-2}=0.1369

P(X=3)=(20C3)(0.2)^3 (1-0.2)^{20-3}=0.2054

And replacing we got:

P(X>3) = 1-[0.0115+0.0576+0.1369+0.2054]= 1-0.4114= 0.5886

Part d

The expected value is given by:

E(X) = np

And replacing we got:

E(X) = 20*0.2= 4

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Answer:

3.6

Step-by-step explanation:

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The maximum weight for a truck on the new York state thruway is 40 tons . How many pounds is this
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The answer is 80,00 pounds.

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At the movie theatre, child admission is $5.40 and adult admission is $9.20 . on thursday, twice as many adult tickets as child
Scorpion4ik [409]
33 child tickets were sold that day.

adult tickets = a
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9.2a + 5.4c = 785.4
a = 2c

Substitute a into the first equation
9.2(2c) + 5.4c = 785.4
Simplify
18.4c + 5.4c = 785.4
Combine like terms by adding
23.8c = 785.4
Divide both sides by 23.8 to isolate the variable c
c = 33
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A 64 ounce bottle of organic orange juice costs $14.72. What is the price
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<em>A 64 ounce bottle of organic orange juice costs $14.72. What is the price </em>

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<em>minute?; </em> 40 words per minute

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