Five times the sum of a number and 27 is greater than or equal to six times the sum of that
1 answer:
The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:
- <em>greater than or equal </em>is written as:
- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
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Answer:
see attached
Step-by-step explanation:
Each digit of the quotient is aligned with the least significant digit of the current dividend. The "current dividend" is that portion of the remaining dividend that is at least 1 and less than 10 times the divisor. The product of the quotient digit and the divisor is subtracted from the "current dividend" to get the remaining dividend.
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For many folks, the hardest part of this algorithm is determining the appropriate quotient digit, and multiplying that by the divisor. Some teachers teach that you start this process by making a list of the multiples of the divisor:
N . . . 28N
1 28
2 56
3 84
4 112
...
This process can be aided by your number sense.
2N is simply N added to itself.
3N is N+2N.
4N is double 2N
5N is half of 10N.
You can proceed to build the table by adding 28 to each previous value, or by recognizing doubles and halves and other sums.
