Answer
x^2 = 7
so yeah u could've looked it up
Answer:
y²/25+x²/4=1
Step-by-step explanation:
The equation for an ellipse is either categorized as
x²/c² + y²/d² = 1 . In such an equation, the vertices on the x axis are categorized by (±c,0) and the vertices on the y axis are (0, ±d)
In the ellipse shown, the vertices/endpoints on the x axis are (-2,0) and (2,0). This means that c is equal to 2. Similarly, on the y axis, the endpoints are (5,0) and (-5,0), so d=5.
Our equation is therefore x²/2²+y²/5²=1 = x²/4+y²/25=1
Our answer is therefore the fourth option, or
y²/25+x²/4=1
Is there any answer choices to what we are looking for?
This is a right angle triangle and you use the Pythagorean theorem to solve for the hypotenuse (the diagonal)
A^2 + B^2 = C^2
8^2 + 8^2 = C^2
64 + 64 = C^2
128 = C^2
C = square_root (128)
C = 11 (to the nearest whole number)
The diagonal is 11 feet (to the nearest whole number)
2.750 + 0.003 + 0.158
= 2.753 + 0.158
<span>= 2.911</span>
