Answer:
The problem implies that we want to write the (average) amount of natural sweeteners consumed per person as a function of time. Let y represent the (average) amount of natural sweeteners consumed per person (in pounds), and let x represent the time measured in years since 1990. That is, x = 0 represents 1990. If y is a linear function of x, then we can use the slope-intercept form y = mx + b (where m is the slope and b is the y-intercept) to write the function.
The slope can be interpreted as the rate of change of y with respect to x, which in this case means the change in consumption of natural sweeteners per year. The statement that consumption has decreased by 0.6 pounds per year tells us that the slope is m = -0.6 Also, the y-intercept is the same as the y-value of the function when x = 0. (In our case, that means time 0, that is, 1990.) Therefore the y-intercept is b = 133. Hope that helps! Let me know if you have any further questions.
Step-by-step explanation:
Answer:
3/2
Step-by-step explanation:
y2 - y1 / x2 - x1
1 - 7 / -5 - (-1)
-6 / -4
= 3/2
Answer:
1000 cm
Step-by-step explanation: I can't explain it sorry.
Answer:
8.090169944 or rounded 8.1
Step-by-step explanation:
Use SOH CAH TOA
Look at x and where it is and what you have.
First thing is to get an angle to use, 36, then to set up your equation.
___(36)=___
Figure out what you have.
You have the hypotonouse, 10, and need the adjacent,x, so you use the equation that involves H for hypotonouse and A for adjacent.
You set up your equation using COS, as you are using CAH.
Cos(36)=x/10
X is over ten sure to CAH C-cos A-adjacent and H-hypotonouse
Switch it around to make it equal to x
10*Cos(36)=x
You input it into your calculator. [10] [COS] [36] [ENTER] and you get the answer.
Round however is needed.
Since there is a common difference of one, this is an arithmetic sequence of the form a(n)=a+d(n-1) which in this case is:
a(n)=15+1(n-1)
All arithmetic sequences have a sum which is equal to the average of the first and last terms time the number of terms, mathematically:
s(n)=(2an+dn^2-dn)/2 (that is just the result of ((a+a+d(n-1))(n/2)) )
Since a=15 and d=1 this becomes:
s(n)=(30n+n^2-n)/2
s(n)=(n^2+29n)/2 so
s(10)=(100+290)/2
s(10)=195 logs
